Author

Catalin
posted 4 posts
since Feb 11, 2012
from

Send key to JUMP TO FILE winamp window

Posted on: 11 Feb 2012

Hi,
I'm trying to send key stroke to winamp Jump to File window, using c#, when is not in foreground but I don't know how.
So far I managed to send keys to winamp like "c" key to toggle play/pause using this example (this example work even when winamp is minimized):

using System;
using System.Diagnostics;
using System.Runtime.InteropServices;

namespace WindowsFormsApplication1
{
    class Test
    {

        [DllImport("User32.Dll", EntryPoint = "PostMessageA")]
        static extern bool PostMessage(IntPtr hWnd, uint msg, int wParam, int lParam);

        [DllImport("user32.dll", CharSet = CharSet.Auto)]
        public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName,
                                                [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName);

       public static void com()
        {
            IntPtr hwnd = FindWindow("Winamp v1.x", null);
            PostMessage(hwnd, 0x100, 0x43, 0);
        }
    }
}

0x43 is the Virtual-Key Code for „C" key.

Can someone help me with this problem and give me an example of haw I can send keys to Jump to File window in winamp?

Vulpes
posted 5419 posts
since Feb 28, 2011
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 11 Feb 2012

According to this link:

http://blog.winamp.com/2008/08/14/keyboard-shortcuts/

the keyboard shortcut for Jump To File is 'J'.

So, I'd send the virtual keycode for 'J' which is 0x4A.

Catalin
posted 4 posts
since Feb 11, 2012
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 12 Feb 2012

Thanks for the answer.

What I want is to send keys to the window (JUMP TO FILE) not to open it. I'm trying to make an application that search a melody in winamp play list by sending keys to this window.
From what I know I have to send keys to a child class of wimamp which is called "Edit", but I don't know how.

I found some examples but it didn't work for me.
I want to use "PostMessage" because I want to be able to sent keys even the window is not in focus.

Thanks.

Vulpes
posted 5419 posts
since Feb 28, 2011
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 12 Feb 2012

Well, you'll need to use FindWindowEx to get the handle for the child window and then send it the keys using PostMessage.

I imagine you've obtained the window class name using Spy++.

The code will be something like this:

[DllImport("user32.dll", CharSet = CharSet.Auto)]

static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChildAfter, string lpszClass, string lpszWindow);

// ...

IntPtr chwnd = FindWindowEx(hwnd, null, "Edit", null);

Catalin
posted 4 posts
since Feb 11, 2012
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 12 Feb 2012

I obtained the name of the class using Winspector.
This is what I found with Winspector:

- 000B099A: BaseWindow_RootWnd „Jump to file"
        - 00090820: BaseWindow_RootWnd „Jump to file"
                - 004E0242: Winamp Gen „Jump to file"
                        - 001707CC: #32770 „Jump to file"
                                - 00200806: Edit

I changed my script into this but with no result.

using System;
using System.Diagnostics;
using System.Runtime.InteropServices;

namespace WindowsFormsApplication1
{
    class Test2
    {

        [DllImport("User32.Dll", EntryPoint = "PostMessageA")]
        static extern bool PostMessage(IntPtr hWnd, uint msg, int wParam, int lParam);

        [DllImport("user32.dll", CharSet = CharSet.Auto)]
        public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName,
                                               [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName);
        [DllImport("user32.dll", CharSet = CharSet.Auto)]

        static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChildAfter, string lpszClass, string lpszWindow);

       public static void comm()
        {

            IntPtr hwnd = FindWindow("Winamp v1.x", null);
            IntPtr chwnd = FindWindowEx(hwnd, IntPtr.Zero, "Edit", null);
            PostMessage(chwnd, 0x100, 0x43, 0);
        }
    }
}

Maybe these are banal questions but I'm very new in c#
Thank you very much for your time.

Vulpes
posted 5419 posts
since Feb 28, 2011
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 12 Feb 2012

Accepted Answer

I think the problem here is that "Edit" is not a child of Winamp's main window but a child of some other window (apparently one with the class name "#32770") down the chain.

What you'll therefore need to do is to repeatedly call FindWindowEx for each level of child window until you eventually drill down to "Edit".

Catalin
posted 4 posts
since Feb 11, 2012
from

Re: Send key to JUMP TO FILE winamp window

Posted on: 13 Feb 2012

Hello again.
Using your advice I managed to send keys to "Jump to File" window.
Below is the script that works perfect for me:

using System;
using System.Diagnostics;
using System.Runtime.InteropServices;

namespace WindowsFormsApplication1
{
class test
{

[DllImport("User32.Dll", EntryPoint = "PostMessageA")]
static extern bool PostMessage(IntPtr hWnd, uint msg, int wParam, int lParam);

        [DllImport("user32.dll", CharSet = CharSet.Auto)]
        public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName,
                                               [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName);
        [DllImport("user32.dll", CharSet = CharSet.Auto)]

static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChildAfter, string lpszClass, string lpszWindow);

public static void comm()
{

            IntPtr hwnd = FindWindow("BaseWindow_RootWnd", null);
            IntPtr chwnd1 = FindWindowEx(hwnd, IntPtr.Zero, "BaseWindow_RootWnd", null);
            IntPtr chwnd2 = FindWindowEx(chwnd1, IntPtr.Zero, "Winamp Gen", null);
            IntPtr chwnd3 = FindWindowEx(chwnd2, IntPtr.Zero, "#32770", null);
            IntPtr chwnd4 = FindWindowEx(chwnd3, IntPtr.Zero, "Edit", null);

            PostMessage(chwnd4, 0x100, 0x43 , 0);


        }

}
}

0x43 is the Virtual-Key Code for „C" key.

Thank you very much for your answer.