lakshmi
how to create a login page using login control in asp.net using windows authentication.?
By lakshmi in ASP.NET on Jun 05 2009
  • sandeep midgule
    Jun, 2009 10

    Dear Laxmi,

             The question itself saying that you are on right track fo .net. please go thro following link you will never forget.

    https://forums.asp.net

    • 0
  • P Narasimha
    Jun, 2009 8
  • P Narasimha
    Jun, 2009 8

    Hi Lakshimi,

    Plz gothrough this code i think it is usefull .

    Here is what the web.config looks like:
    <?xml version="1.0" encoding="utf-8" ?>
    <configuration>
    <system.web>
    <authentication mode="Windows">
    <forms name="imper2" protection="All" timeout="80" loginUrl="login.aspx" path="/"></forms>
    </authentication>
    <identity impersonate="true"></identity>
    <authorization>
    <deny users="?"></deny>
    </authorization>
    </system.web>
    </configuration>


    Here is what the login.aspx looks like

     <%@ Language=VBScript Debug="True" %>
     <%@ Import Namespace="System.Web" %>
     <%@ Import Namespace="System.Security.Principal" %>
     <%@ Import Namespace="System.Runtime.InteropServices" %>
     <%@ Import Namespace="System" %>
    <html> <head> <script runat="server"> Dim LOGON32_LOGON_INTERACTIVE As Integer = 3 Dim LOGON32_PROVIDER_DEFAULT As Integer = 0 Declare Auto Function LogonUser Lib "advapi32.dll" (lpszUsername As String, _ lpszDomain As String, _ lpszPassword As String, _ dwLogonType As Integer, _ dwLogonProvider As Integer, _ ByRef phToken As IntPtr) As Integer Declare Auto Function DuplicateToken Lib "advapi32.dll" (ByVal ExistingTokenHandle As IntPtr, _ ImpersonationLevel As Integer, _ ByRef DuplicateTokenHandle As IntPtr) As Integer Instantiate a WindowsImpersonationContext Dim impersonationContext As WindowsImpersonationContext Dim currentWindowsIdentity As WindowsIdentity The page load function this page loads on startup Sub Button_Click(s As Object, e As EventArgs) If impersonateValidUser(txtUsername.Text, txtDomain.Text, txtPassword.Text) Then Response.Write(User.Identity.Name) undoImpersonation() Else Response.Write("We're sorry, we were not able to impersonate you!") End If End Sub Private function impersonateValidUser() returns a boolean indicating if the function call was successful or failed Private Function impersonateValidUser(userName As String, domain As String, password As String) As Boolean 'Dim userName As String = txtUsername.Text 'Dim domain As String = txtDomain.Text 'Dim password As String = txtPassword.Text Dim tempWindowsIdentity As WindowsIdentity Dim token As IntPtr Dim tokenDuplicate As IntPtr If LogonUser("teacher", "mydomain", "*****", LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, token) <> 0 Then If DuplicateToken (token, 3, tokenDuplicate) <> 0 Then tempWindowsIdentity = New WindowsIdentity(tokenDuplicate) impersonationContext = tempWindowsIdentity.Impersonate() If impersonationContext is Nothing Then impersonateValidUser = false Else impersonateValidUser = true End If Else impersonateValidUser = false End If Else impersonateValidUser = false End If End Function 'reverse the impersonation operation and go back to the original permissions Private Sub undoImpersonation() impersonationContext.Undo() End Sub </script> <meta name="GENERATOR" Content="Microsoft Visual Studio.NET 7.0"> </head> <body> <form runat="server"> <h3>Please login here:</h3> <hr> Username: <asp:TextBox Runat="server" ID="txtUsername" TextMode=SingleLine></asp:TextBox> <br> Domain: <asp:TextBox Runat="server" ID="txtDomain" TextMode=SingleLine></asp:TextBox> <br> Password: <asp:TextBox Runat="server" ID="txtPassword" TextMode=Password></asp:TextBox> <br> <asp:Button Runat="server" Text="Login" OnClick="Button_Click"></asp:Button> </form> </body> </html> Thanks
    Narasima


     

    • 0
  • Murali Krishna Ravi
    Jun, 2009 8

    Hi lakshmi
    we have a login control in toolbox
    u just drag and drop to webpage.then u open web.config file. in that we have seen that
    <forms authentication mode="windows"/>
    if u can change authentication mode into <forms authentication mode="forms"/>
    -> u can go to website menu. in that we have a option websiteadminisration tool-> u can go to->security tab.-> then create users who ar logged into page.



    • 0
  • lakshmi
    Jun, 2009 5

    pls help me, its very urgent.

     

     

    regards,

    swathi

    • 0


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