ceiling an integer in C#

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• 

  Sanjeeb Lenka13y agoPosted Sep 15, 2013, 3:02 PM

  Accepted answer

  hi,
  try this:
  
  sample:
  
  using System;
  using System.Collections.Generic;
  using System.Linq;
  using System.Text;
  
  namespace ConsoleApplication1
  {
      class Class2
      {
          static void Main(string[] args)
          {
              Console.WriteLine("Enter a number");
              int numberFloor = Convert.ToInt32(Console.ReadLine());
              decimal a = (decimal)numberFloor / 3;           
              decimal res = Math.Round(a);
              int heightGroupBox = ((Convert.ToInt32(res)* 25) + 30);          
              Console.WriteLine(heightGroupBox);
              Console.ReadKey();
  
          }
      }
  }
  
  
  if you want to write it in a single line try this:
  
  int heightGroupBox = ((Convert.ToInt32(Math.Round((decimal)numberFloor / 3)) * 25) + 30);
  
  
  
  
• 

  Vulpes13y agoPosted Sep 16, 2013, 7:29 AM

  Perform the calculation using double arithmetic (change 3 to 3.0) and then use the Math.Ceiling method:

  
  

  int heightGroupBox = (int)Math.Ceiling(numberFloor / 3.0) * 25 + 30;