Conditional rendering in React js

Let's try conditional function to return the icon you can print status value in console and check if it is correct:
 
function renderButton(likeStatus)
{
if(likeStatus){
return();
}
}

{this.renderButton(likes.likes_status)}

Hi,

I think there is some issue with that condition:

Try below code

{likes.likes_status ? :    null }  

Don't use likes.likes_status =true, Use likes.likes_status  == true or don't use any comparison value it will automatiocally check for true value.

1. {likes.likes_status?"LikeButton" style={{background:'transparent',border:'none'}}>"colorlink">class="fa fa-thumbs-up">:null }