How to get int math.random round number?

Abhilash J A

Hi,

Let's say, if I want to set Math.random(); in variable.

'idPartnerProject' model class object, some times it will cotain integer also,

foreach (var partnerProjecttemp in pageVM.Form5.Projects)
{
partnerProjectBL.idPartnerProject = Convert.ToInt32(partnerProjecttemp.idPartnerProject);
/*if idPartnerProject id existing then update record, not exist add a new record*/
}

And,

But now error raising, Input string was not in a correct format.

How can I solve this?

6 Replies

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Nitin Sontakke9y ago
Dear Abhilash, these are all very minor things! If it is string, can you not use float.Parse() method to get float?

Is this someone else's code? Have you written class with that property? Why that property is String in first place? Think from all the angles and resolve.

You can add some minor check to check if it is zero and stuff like that.
Asma Khalid9y ago
Do as follow i.e.
int value = Convert.ToInt32(Math.Round(Math.Random));
partnerProjectBL.idPartnerProject = value;
Abhilash J A9y ago
Excuse me Nitin Sir,

the 'idPartnerProject' is being string datatype

Then, how can I solve the error?
partnerProjectBL.idPartnerProject = Convert.ToInt32(partnerProjecttemp.idPartnerProject);
OR
If random number is coming, that is the id not existing in db. Then 'partnerProjectBL.idPartnerProject = 0' return zero. How can I do this?
Nitin Sontakke9y ago
Yes, it will. But now you have the integer part. And you do something as follows:
float d = 0.972283766387763F;
float x = d * 1000;
int y = Convert.ToInt32(x);
DO NOT COPY AND PASTE ABOVE CODE. Please give meaningful variable names. I was lazy to type meaningful names. This is for demonstration purpose only.
Abhilash J A9y ago
Hello Nitin Sir,

Still it 'idPartnerProject' holding decimal number.
Nitin Sontakke9y ago
Why not multiply the result by 100 or 1000 depending on how many digits integer you want?