Show Image in GridView Using ASP.NET

In this article I explain how to insert an image into our project folder and insert an image of a path in the database and show images in a GridView. 

First I created a database EmpDetail. Now I will create a table in this database. 

Query Code

CREATE TABLE [dbo].[Image_Details](

      [ImageId] [int] IDENTITY(1,1) NOT NULL,

      [ImageName] [varchar](50) NULL,

      [Image] [nvarchar](max) NULL


Now insert some data into the LoginDetail table.

Now the following procedure is used.

Step 1

Open Visual Studio 2012 and click "File" -> "New" -> "Web site...". A window is opened. In this window, select "Empty Web Site Application" under Visual C#.


Give the name of your application as "Display_Image_in_Gridview" and then click "Ok".

Step 2

Now we will need to add a folder to our website, check the following procedure.
Go to Solution Explorer then right-click on the solution then select "Add" then select "New Folder". Then provide the name of this folder.


Complete Program


<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Display_Image.aspx.cs" Inherits="Display_Image" %>

<!DOCTYPE html>

<html xmlns="">

<head runat="server">




    <form id="form1" runat="server">

     <h3 style="color: #0000FF; font-style: italic">Display Image in GridView Using ASP.NET</h3>


    <asp:FileUpload ID="fileupload" runat="server" />

        <br />

        <asp:Button ID="upload" runat="server" Font-Bold="true" Text="Upload" OnClick="upload_Click" />

        <br />

        <br />



            <asp:GridView runat="server" ID="gdImage" HeaderStyle-BackColor="Tomato"  AutoGenerateColumns="false">


                    <asp:BoundField DataField="ImageId" HeaderText="ImageId" />

                    <asp:BoundField DataField="ImageName" HeaderText="ImageName" />

                    <asp:ImageField DataImageUrlField="Image" HeaderText="Image"></asp:ImageField>                   









using System;

using System.Collections.Generic;

using System.Linq;

using System.Web;

using System.Web.UI;

using System.Web.UI.WebControls;

using System.Data;

using System.Data.SqlClient;

using System.IO;

using System.Configuration;

public partial class Display_Image : System.Web.UI.Page


    SqlConnection con;

    SqlDataAdapter da;

    DataSet ds;

    SqlCommand cmd;

    protected void Page_Load(object sender, EventArgs e)




    protected void upload_Click(object sender, EventArgs e)




            string filename = Path.GetFileName(fileupload.PostedFile.FileName);

            fileupload.SaveAs(Server.MapPath("~/Images/" + filename));

            con = new SqlConnection(ConfigurationManager.ConnectionStrings["ImageSql"].ConnectionString);


            cmd = new SqlCommand("insert into Image_Details (ImageName,Image) values(@ImageName,@Image)", con);

            cmd.Parameters.AddWithValue("@ImageName", filename);

            cmd.Parameters.AddWithValue("@Image", "Images/" + filename);


            da = new SqlDataAdapter("select * from Image_Details",con);

            ds = new DataSet();


            gdImage.DataSource = ds;



        catch (Exception ex)


            upload.Text = ex.Message;







For more information, download the attached sample application.


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