GridView With RadioButton Binding

Introduction

This article demonstrates an interesting and very useful concept in GridView.

Question: What is a GridView with Radio Button Binding?

In simple terms, it enables binding to the GridView, by selecting an appropriate radio button item in a grid.

Step 1: Create a new web application

Step 2: The complete code of WebForm1.aspx is as in the following:

<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="GridViewRadioButtonBindApp.WebForm1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<center>
<div>
<table>
<tr>
<td colspan="2" align="center">
<asp:Label ID="Label1" runat="server" Text="GridView Radio Button Bind App" Font-Bold="true"
Font-Size="Large" Font-Names="Verdana" ForeColor="Maroon"></asp:Label>
</td>
</tr>
<tr>
<td colspan="2" align="center">
<asp:GridView ID="GridView1" runat="server" CssClass="grid" BackColor="LightGoldenrodYellow"
BorderColor="Tan" BorderWidth="1px" CellPadding="2" AutoGenerateColumns="false"
ForeColor="Black" GridLines="None" OnRowDataBound="GridView1_RowDataBound">
<AlternatingRowStyle BackColor="PaleGoldenrod" />
<FooterStyle BackColor="Tan" />
<HeaderStyle BackColor="Tan" Font-Bold="True" />
<PagerStyle BackColor="PaleGoldenrod" ForeColor="DarkSlateBlue" HorizontalAlign="Center" />
<SelectedRowStyle BackColor="DarkSlateBlue" ForeColor="GhostWhite" />
<SortedAscendingCellStyle BackColor="#FAFAE7" />
<SortedAscendingHeaderStyle BackColor="#DAC09E" />
<SortedDescendingCellStyle BackColor="#E1DB9C" />
<SortedDescendingHeaderStyle BackColor="#C2A47B" />
<Columns>
<asp:TemplateField HeaderText="FirstName">
<ItemTemplate>
<asp:Label runat="server" ID="lblFName" Text='<%# Bind("FirstName") %>'></asp:Label></ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="LastName">
<ItemTemplate>
<asp:Label runat="server" ID="lblLName" Text='<%# Bind("LastName") %>'></asp:Label></ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Gender">
<ItemTemplate>
<asp:RadioButtonList ID="RadioButtonList1" runat="server">
<asp:ListItem Text="Male" Value="1"></asp:ListItem>
<asp:ListItem Text="Female" Value="2"></asp:ListItem>
</asp:RadioButtonList>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
</td>
</tr>
</table>
</div>
</center>
</form>
</body>
</html>

Step 3: The complete code of WebForm1.aspx.cs is as in the following:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
using System.Data;
namespace GridViewRadioButtonBindApp
{
public partial class WebForm1 : System.Web.UI.Page
{
SqlConnection con = new SqlConnection("Data Source=WIN-KV3BO1RQQF7;Initial Catalog=Company;Integrated Security=True");
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack) { con.Open();
SqlCommand cmd = new SqlCommand("select FirstName, LastName, Gender from Employee", con);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataSet ds = new DataSet();
da.Fill(ds);
con.Close();
GridView1.DataSource = ds;
GridView1.DataBind();
}
}
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
int genderValue = (int)DataBinder.Eval(e.Row.DataItem, "Gender");
RadioButtonList rb = (RadioButtonList)e.Row.FindControl("RadioButtonList1");
rb.Items.FindByValue(genderValue.ToString()).Selected = true;
}
}
}
}

Step 4: The output for the application is shown below:

I hope this article was useful for you.

4 Comments

Join the conversation! Your thoughts help the community grow.

Yapa Appuhamy6y ago
Superb Code.. Working fine.. Thanks lot.
Anil (BABU)7y ago
Can u explain how to insert this values in database
صاله البرق11y ago
thanks for this code .. but i need help . what if i want use button to insert that name and gender in table in sql .. can you write that code please .. really i need it , hope you can help me
Gowtham Rajamanickam11y ago
good....