Post Multiple File And Data With The Use Of Single Model API Call In .NET Core With Angular


In this article, we will learn about how to post file and data with the use of .Net Core WebAPI And Angular.

We can better understand this step by step.

Step 1

First we will create one model in Angular Application like,    

export interface CreateDocument {
    Id: number,
    firstName: string,
    lastName: string,
    uploadedPhotoorDocName: string[]

Step 2

Now first of all selected file put into file array like 

2.1 Create File Array,        

public filecontent: File[] = [];    

2.2 Angular Html template bind event,

<input id="file" class="form-control" type="file" multiple name="uploadedDocumentFile" [(ngModel)]="createDocument.uploadedDocumentFile" (change)="onFileSelected($event)" />

2.3 Selected File put into filecontent array when user select multiple files,    

onFileSelected(e: any) {
    for (var i = 0; i <; i++) {

Step 3

All file and model data put into FormData object 

3.1 First create FormData object like,        

let myFormData: FormData = new FormData();

3.2 Now one by one push all model value into FormData Object        

myFormData.append("Id", "1001");
myFormData.append("firstName", "xyz");
myFormData.append("lastName", "abc");

3.3 All push selected file into FormData Object like

let files: File[] = this.filecontent;
for (let i = 0; i < files.length; i++) {
    let file: File = files[i];
    myFormData.append("files", file,; // the filed name is `files` because the server side declares a `Files` property

3.4 If pass array value in FormData object then convert as JSON.stringify() array like 

let docname = ["testing.doc", "testing1.doc", "testing2.doc"];
myFormData.append("uploadedPhotoorDocName", JSON.stringify(docname));

Step 4. Call API Form Angular

4.1 Pass Formdata into service.    

this.servicename.CreateOrUpdate(myFormData).subscribe((dataResult: CommonResponse) => {
    if (dataResult && dataResult.status == true) {}

4.2 Service call API like,    

createOrUpdate(createDocument:FormData): Observable<CommonResponse> {
return<CommonResponse>(`${environment.apiUrl}` + this.getUrl + "/Save",createDocument)
        catchError(this.handleError('Error', []))

Step 5

Now we implement POST API .NET Core                 

5.1 First of all create model,

public class DemoModel {
    public int Id {
    public string ? FirstName {
    public string ? LastName {
    public string[] UploadedPhotoorDocName {
    public IList < IFormFile > Files {
public IActionResult SaveSiteDocument([FromForm] DemoModel demoModel) {
    string webRootPath = new CommonHelper(_webHostEnvironment).GetRootPath();
    string saveFilePath = webRootPath + "//" + basePath + "//" + siteName + "_" + demoModel.FirstName;
    SiteDocumentServices siteDocumentServices = new SiteDocumentServices();
    for (int i = 0; i < demoModel.uploadedPhotoorDocName.Length; i++) {
        string strDocumentFile = demoModel.UploadedPhotoorDocName[i];
        string fileName = System.IO.Path.GetFileName(strDocumentFile);
        bool result = siteDocumentServices.SaveFile(strDocumentFile, saveFilePath, fileName);
        demoModel.Id = demoModel.Id;
        demoModel.FirstName = demoModel.FirstName;
        demoModel.LastName = demoModel.LastName;;
        demoModel.UploadedPhotoorDocName = demoModel.UploadedPhotoorDocName[i];;
    var response = new {
        Message = "records saved successfully",
            Status = true,
            HasException = false,
            data = message
    return (IActionResult) Ok(response);


Nowadays some applications require post data with some documents, Images. So this article is very helpful to save data and file from database and store files in server folder. 

Enjoy Coding !!!!

We have got the response. Fantastic!  The API post file with data saves into database and the file is stored in a specific folder in the server.

Thank you for reading my article. Please leave your comments in the comment box below.

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