Project Euler - Problem 6 - Sum Square Difference

This code snippet for Sum Square Difference.

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

int sumOfSquares = 0, squareOfSum = 0;
for (int i = 1; i <= 100; i++)
{
    sumOfSquares += (i * i);
    squareOfSum += i;
}
Console.WriteLine((squareOfSum *
    squareOfSum) - sumOfSquares);

Output : 25164150