Linear search using Java

// linear search program

import java.io.*;
class ssvlin
{
 public static void main(String args[]) throws IOException
 {

  System.out.println("From equations ax1 + bx1= m ; cx1+dx1 = n");
    DataInputStream  dis = new DataInputStream(System.in);
    System.out.print("Enter your   'a'       number     :");
    int a  = Integer.parseInt(dis.readLine());
    System.out.print("Enter your   'b'  number     :");
    int b  = Integer.parseInt(dis.readLine());
    System.out.print("Enter your   'c'  number     :");
    int c  = Integer.parseInt(dis.readLine());
    System.out.print("Enter your   'd'  number     :");
    int d  = Integer.parseInt(dis.readLine());
    System.out.print("Enter your   'm'  number     :");
    int m  = Integer.parseInt(dis.readLine());
    System.out.print("Enter your   'n'  number     :");
    int n  = Integer.parseInt(dis.readLine());

    int   dina = (a * d) - (c * b);
    int   numr1 = (m * d) - (b * n);
    int   numr2 = (n * a) - (m * c);
           System.out.println("your number     :"  + dina);
           System.out.println("your number     :"  + numr1);
           System.out.println("your number     :"  + numr2);

    if (dina==0)
   {
   System.out.println("The value (ad-cb)becomes Zero");
   }
   else
   {
    double x1 = numr1 / dina;
    System.out.println("Result x1      :"  + x1);
    double x2 = numr2 / dina;
    System.out.println("Result x2      :"  + x2);
    }
  }
}