Code to Start an Exe Application using C# Console Application

How to start an .exe application using C# console application.

Ans: namespace required is:

using System.Diagnostics;

Process process2 = new Process();
process2.StartInfo.FileName = DestinationPath + "\\" + FileName + "\\AutoUpdater.exe";
process2.StartInfo.Arguments = string.Format("{0}", DestinationPath + "\\" + FileName + "\\AutoUpdater.exe");
process2.StartInfo.CreateNoWindow = true;
try
{
   //Start Autoupdater.exe
   process2.Start();
   if (process2.WaitForExit(180 * 60 * 1000))
   {
      Console.WriteLine("16. Auto Updater exited normally at " + DateTime.Now.ToString() + "\n");
   }
   else
   {
      process2.Kill();
      Console.WriteLine("16. Auto Updater exited forcefully at " + DateTime.Now.ToString() + "\n");
   }
}
catch (Exception ex)
{
   Console.WriteLine("16. error to kill auto updater process, Message: " + ex.Message);
}