About Regular Expressions using Groups

Question

Hello All,

I want to break the string by using the Regular Expression:

String:"((ALLRAD + !(812_ENGLAND, US))" or (((ALLRAD + !(812_ENGLAND, US)))"
or ((((ALLRAD + !(812_ENGLAND, US))))"

Output:"(ALLRAD + !(812_ENGLAND))"
"(ALLRAD + !(US))"

Thanks in Advance

Vulpes · Answer

This is just a generalization of the expression in your previous thread: http://www.c-sharpcorner.com/forums/thread/252590/about-regular-expressions.aspx The following should deal with any number of brackets at either end of the text: using System; using System.Text.RegularExpressions; class Test { static void Main() { string[] strs = { "ALLRAD + !(812_ENGLAND, US)", "(ALLRAD + !(812_ENGLAND, US)", "((ALLRAD + !(812_ENGLAND, US))", "(((ALLRAD + !(812_ENGLAND, US)))", "((((ALLRAD + !(812_ENGLAND, US))))" }; string regExp = @"^$*(\w+\s*\+\s*(!)?)\((\w+(,\s*\w+)*)$*$"; for(int i = 0; i { Match m = Regex.Match(strs[i], regExp); string[] split = Regex.Split(m.Groups[3].Value, @",\s*"); string[] output = new string[split.Length]; for(int j = 0; j { output[j] = String.Format("({0}({1}))", m.Groups[1], split[j]); Console.WriteLine(output[j]); } Console.WriteLine(); } Console.ReadKey(); } } The output is: (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US))

About Regular Expressions using Groups

Answers (1)