Are there are any way to get partc without make join by Verification H

Question

I work on sql server 2014
I need to get partc as expected result
Actualy i need partc from table #partsc that have Verification Hash on table #VervicationCode
are there are any way to get part c without join with Verification Hash

create table #partsc
 (
 partc int,
 [VerificationHash] VARBINARY(512) NULL 
 )
 insert into #partsc(partc,VerificationHash) 
 values
 (11234,0x566B391EDEB07A47B17B89265ABE19850655885D83247AE7E7C28849D8873A31F56D139E4987BFE85B476035E39B7308C5D203955A238F92D5A2096B50AD674C),
 (15431,0x5677965D16CEEDC754EAED74780662518E132F08C1B6CFF67BE62D21100C3B4C63E09937BB7153CDE67550F957AFBB23658B2193EB842FC173A8F8460DED246D),
 (67501,0x569132E995038072EA4AE52DC760FCB2C21AE1A6F047C66FF86B483BF575DE2EF412B3B10CDC8B8DC8B8D31D28BF90442C31811F13EC5B49DE1EBC008B6EEF16),
 (87190,0x56C5668A7FCB015D39EE602FAC80124050D0ADCA684D77FC99D7C293DCC09DA1A4FA2514F89E86D7619AE20A72C6CAE2A7BFE776F89C5494C36994C84241D705),
 (987610,0x56E0315397B4A932570101661B449FC41DF9683F5EDCC7387A8C9FA8E357A06FCF1989587CCF3E0548F79F36BB2F5C91BF6CD9E988EA9922C5C865A043B51B1F),
 (89871,0x57B1B8FF59BFE3F788AA1C6D5CFFC40D54F0D494D60B43CED1B52C1E290CC8AE62C3E1220365F1DCB0A00688AF92222DC32CC5454DCF9572812735D9FAF7E3C7),
 (12909,0x57DAFCAA14E6561FD8C2109627732DFDBEC5E169682080EF1107FA96ED505CC18BD22924BFA19A1A346BB15440FF48F53202A88672AD6FC66F4DAF0D518BC69C)
    
 create table #VervicationCode
 (
 [VerificationHash] VARBINARY(512) NULL 
 )
 insert into #VervicationCode(VerificationHash) 
 values
 (0x5677965D16CEEDC754EAED74780662518E132F08C1B6CFF67BE62D21100C3B4C63E09937BB7153CDE67550F957AFBB23658B2193EB842FC173A8F8460DED246D),
 (0x569132E995038072EA4AE52DC760FCB2C21AE1A6F047C66FF86B483BF575DE2EF412B3B10CDC8B8DC8B8D31D28BF90442C31811F13EC5B49DE1EBC008B6EEF16),
 (0x56C5668A7FCB015D39EE602FAC80124050D0ADCA684D77FC99D7C293DCC09DA1A4FA2514F89E86D7619AE20A72C6CAE2A7BFE776F89C5494C36994C84241D705),
 (0x56E0315397B4A932570101661B449FC41DF9683F5EDCC7387A8C9FA8E357A06FCF1989587CCF3E0548F79F36BB2F5C91BF6CD9E988EA9922C5C865A043B51B1F)

expected result will be :

partc
15431
67501
87190
987610