avoid WPF form duplicate open and activate open forms

Dhanushka Amarasinghe

8y6.7kLearn iOS Programming

i'm developing WPF application, so my requirments are

when client open a form (Child form) from my application

if (check already open)

{

Activate Open form/ when its hide or minimize need activate/ not new object

}

else

{

open new object of relavent form

}

9 Replies

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Amit Gupta8y ago
Accepted answer
It will not take a pain to implement it.

MainWindow.xaml part
FormTwo frm;
private void button_Copy_Click(object sender, RoutedEventArgs e)
        {

if(frm== null)
      frm = new FormTwo();

// you need to take care of form closing because the object being disposed)
frm.Closed += delegate {frm=null;};

if(frm.WindowState == WindowState.Minimized)
   frm.WindowState = WindowState.Normal;

frm.Show();
frm.Activate();
       }
Dhanushka Amarasinghe8y ago
Thanx , Its happened
Dhanushka Amarasinghe8y ago
Can u appy and upload it,
Amit Gupta8y ago
In your sample code, you haven't applied the code that I had posted, it will restrict opening the same form twice
Dhanushka Amarasinghe8y ago
i have uploaded my sample code,

FormOne - can open any number of dublicate forms

FormTwo - vlidate/aoid dublicate open only, cannt activate/ select or view open form

refer my code
Dhanushka Amarasinghe8y ago
No amith, its not working, cannt activate already open form(wpf form)
Amit Gupta8y ago
This can be done in a optimized way like
Form2 frm;
void OpenForm()
{
   if(frm== null)
      frm = new Form2();

// you need to take care of form closing because the object being disposed)
frm.Closed += delegate {frm=null;};

if(frm.WindowState == WindowState.Minimized)
   frm.Window = WindowState.Normal;

frm.Show();
frm.Activate();
}
Dhanushka Amarasinghe8y ago
this is code now i can avoid duble open same form in my application

var allWindows = Application.Current.Windows;
bool Reslt = false;
string typeName;
foreach (var window in allWindows)
{
Window win = window as Window;
string name = win.Name;
typeName = win.GetType().Name;
if (typeName == "FormTwo") // FormTwo my form name as "FormTwo"
Reslt = true; // check its open
}
if (Reslt == false)
{
FormTwo objFrm = new FormTwo();
objFrm.Show();
}
else
{
FormTwo objFrm = new FormTwo();
objFrm.Activate(); // this is not working
}
Amit Gupta8y ago
As you are having logic, have you tried implementing it?