Can any one tell me why there's an error in my if statement code

Question

https://del.dog/Line12 Can any one tell me why there's an error in my if statement code

Rajanikant Hawaldar · Answer

You didn't read this->However you also forgot to close a parenthesis there.

Rajanikant Hawaldar · Answer

Python programmers hate unindented code or unmatching parentheses

Rajanikant Hawaldar · Answer

Then why do you use def when calling the function.

Raghavendra · Answer

I was too focused on correcting the if statement that I forgot to even go through the code all over again

Raghavendra · Answer

Yeah thanks @Rajanikant I literally had to count the parentheses all again

Raghavendra · Answer

Yeah thanks @Rajanikant I literally had to count the parentheses all again

Raghavendra · Answer

I just remembered now

Raghavendra · Answer

I just remembered now

Raghavendra · Answer

The function name with brackets Like function()

Rajanikant Hawaldar · Answer

How will you call a function?

Raghavendra · Answer

I don't need to declear it to call it again

Rajanikant Hawaldar · Answer

+1, exactly....ONLY to declare a function. And how will you call a declared function then? However you also forgot to close a parenthesis there.

Raghavendra · Answer

Declaring a function

Rajanikant Hawaldar · Answer

Please use Syntax Highlighter Code to post code. What do you think def is used for?

Raghavendra · Answer

def positive(): cuberoot = (num ** (1/3)) print(int(cuberoot)) def negative(): cuberoot = (-(-num) **(1/3)) print(int(cuberoot)) num = int(input('
: ' ) if num>0: positive() elif num<0: negative() else: print('Enter a Valid number')

Rajanikant Hawaldar · Answer

Hey raghav, i will help you if can post your code instead of that external link

Can any one tell me why there's an error in my if statement code

Answers (16)