create different xml files by an attribute value

darma teja

Hi All,

Give me some light to do this one:
My sample xml file is here:

blabla

blabla

blabla

blabla

blabla

blabla
blabla

I would like to create different xml files based on . All same id2= "HIN" attributes including parent node () and root node () should be in the one xml file. All same id2= "TEL" attributes including parent node () and root node () should be in second xml file. All same id2= "ARA" attributes including parent node () and root node () should be in the one xml file.

Advance thanks,
Darma

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes11y ago
Accepted answer
Try this:

using System;
using System.Linq;
using System.Xml.Linq;

class Program
{
static void Main()
{
XDocument doc = XDocument.Load("darma.xml");
XElement root = doc.Root;
XElement HIN = new XElement(root);
HIN.RemoveNodes();
XElement TEL = new XElement(root);
TEL.RemoveNodes();
XElement ARA = new XElement(root);
ARA.RemoveNodes();

foreach(XElement child1 in root.Elements("child1"))
{
XElement child = child1.Element("child");
switch(child.Attribute("id2").Value)
{
case "HIN":
HIN.Add(child1);
break;

case "TEL":
TEL.Add(child1);
break;

case "ARA":
ARA.Add(child1);
break;

default:
break;
}
}

HIN.Save("HIN.xml");
TEL.Save("TEL.xml");
ARA.Save("ARA.XML");
}
}

The contents of the resulting files are:

/* HIN.xml */

blabla

blabla

blabla

/* TEL.xml */

blabla

blabla

/* ARA.xml */

blabla
blabla

I've assumed you'll want to copy the description and target nodes to the respective files as well but, if not, it's easy to remove them.
Manish Kumar Choudhary11y ago
Hi darma teja,
Go through following links it will help you

http://www.codeproject.com/Articles/8574/Generate-dynamic-ASP-NET-pages-by-using-XML-and-XS

http://www.codedigest.com/Articles/ASPNET/377_Reading_and_Writing_XML_files_in_C__and_ASPNet.aspx