CSharp To Define a method which returns the next multiple of 100 for t

Question

Define a method which returns the next multiple of 100 for the given number.. can any one help me out

Sachin Singh · Answer

what do you mean by next multiple of 100? 200,300,......are all multiple of 100. if someone enters 5 then 500 will be next multiple of 100, what do you want to achieve?

Sachin Singh · Answer

var x= NextMultiple(1497); Console.WriteLine(x); // 1500 Console.ReadLine(); } public static int NextMultiple( int n) { if (n { return -1; } int a = (n / 100); int x=(a+1)*100; return x; }

sankeerth m · Answer

Thanks For respone. This is the question bro. Define a method which returns the next multiple of 100 for the given number. Write the method with the following specifications: Name of method getNextMultipleOf100() // which accepts an integer value as argument and return the next multiple of 100. Arguments: one argument of type integer Return Type: an integer value Specifications: The value returned by the method getNextMultipleOf100() is determined by the following rules: if the given value is negative or zero, return -1 if the given value is positive, return the next multiple of the given number. Example: if x = 123, return 200.

CSharp To Define a method which returns the next multiple of 100 for t

Answers (3)