CSharp To Define a method which returns the next multiple of 100 for t

sankeerth m

Define a method which returns the next multiple of 100 for the given number..

can any one help me out

3 Replies

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Sachin Singh5y ago
Accepted answer
what do you mean by next multiple of 100?
200,300,......are all multiple of 100.
if someone enters 5 then 500 will be next multiple of 100, what do you want to achieve?
Sachin Singh5y ago
var x=   NextMultiple(1497);

           Console.WriteLine(x);  // 1500
           Console.ReadLine();
       }


       public static int NextMultiple(int n)
       {
           if (n <= 0)
           {
               return -1;
           }
           int a = (n / 100);
           int x=(a+1)*100;
           return x;



       }
sankeerth m5y ago
Thanks For respone.

This is the question bro.

Define a method which returns the next multiple of 100 for the given number.
Write the method with the following specifications:
Name of method getNextMultipleOf100() // which accepts an integer value as argument and return the next multiple of 100.
Arguments: one argument of type integer
Return Type: an integer value
Specifications: The value returned by the method getNextMultipleOf100() is determined by the following rules:
if the given value is negative or zero, return -1
if the given value is positive, return the next multiple of the given number. Example: if x = 123, return 200.