Datagrid selection changed for image?

Goran Bibic

8y806Learn iOS Programming

Problem is selection cahnged for images in datagrid...

private void roba_uslugeDataGridView_SelectionChanged(object sender, EventArgs e)
{
if (roba_uslugeDataGridView.SelectedRows.Count > 0)
{
string id = roba_uslugeDataGridView.SelectedRows[0].Cells[0].Value.ToString();
string sifra = roba_uslugeDataGridView.SelectedRows[0].Cells[1].Value.ToString();
string naziv = roba_uslugeDataGridView.SelectedRows[0].Cells[2].Value.ToString();
dataPictureBox.Image = null;
idTextBox.Text = id;
sifraTextBox.Text = sifra;
imeTextBox.Text = naziv;
byte[] img_arr = null;
MemoryStream ms = new MemoryStream();
dataPictureBox.Image.Save(ms, dataPictureBox.Image.RawFormat);
img_arr = ms.GetBuffer();
}
}

11 Replies

Know the answer? Post it — somebody with the same question will find it here.

Rafnas T P8y ago
Accepted answer
hi i have updated code check below
private void roba_uslugeDataGridView_SelectionChanged(object sender, EventArgs e)
        {
            if (roba_uslugeDataGridView.SelectedRows.Count > 0)
            {

                string id = roba_uslugeDataGridView.SelectedRows[0].Cells[0].Value!=null?roba_uslugeDataGridView.SelectedRows[0].Cells[0].Value.ToString():"";
                string sifra = roba_uslugeDataGridView.SelectedRows[0].Cells[1].Value!=null?roba_uslugeDataGridView.SelectedRows[0].Cells[1].Value.ToString():"";
                string naziv = roba_uslugeDataGridView.SelectedRows[0].Cells[2].Value!=null?roba_uslugeDataGridView.SelectedRows[0].Cells[2].Value.ToString():"";

try{
          if(roba_uslugeDataGridView.SelectedRows[0].Cells["data"].Value!=null)
         {
byte[] ap =(byte[])roba_uslugeDataGridView.SelectedRows[0].Cells["data"].Value;
                MemoryStream ms = new MemoryStream(ap);
                dataPictureBox.Image = System.Drawing.Image.FromStream(ms);
     }
else{ dataPictureBox.Image =null;}
              }catch{}
                idTextBox.Text = id;
                sifraTextBox.Text = sifra;
                imeTextBox.Text = naziv;
            }
        }
Goran Bibic8y ago
Line 17 error is
; expected
Goran Bibic8y ago
Button refresh say this error
,,Unable to cast object of type 'System.DBNull' to type 'System.Byte[]'.,,
Goran Bibic8y ago
Code work but just have only 1 row
Goran Bibic8y ago
When open form have just one value from datagrid...fir value in sql...if click refresh...error....but if think becose no have all rows images ...maybe null row and becose error
Goran Bibic8y ago
byte[] ap = ///here mus be two ((byte[])roba_uslugeDataGridView

Thas ok...I have now another problem...work but i have just first row in datagreed, when ope... Ihave 25 rows
Rafnas T P8y ago
ya, you can use System.Drawing.Image
Goran Bibic8y ago
Error CS1002 ; expected

BSS C:\Users\Bibic Goran\Documents\Visual Studio 2015\Projects\BSS\BSS\roba_i_usluge.cs Line 10 Active

Error CS1513 } expected
BSS C:\Users\Bibic Goran\Documents\Visual Studio 2015\Projects\BSS\BSS\roba_i_usluge.cs Line 10 Active

Error CS0104 'Image' is an ambiguous reference between 'System.Drawing.Image' and 'iTextSharp.text.Image'
BSS C:\Users\Bibic Goran\Documents\Visual Studio 2015\Projects\BSS\BSS\roba_i_usluge.cs Line 12 Active

Here I need to choose System.Drawing.Image becose iTextSharp.text.Image using for PDF
Rafnas T P8y ago
try below code,
private void roba_uslugeDataGridView_SelectionChanged(object sender, EventArgs e)
        {
            if (roba_uslugeDataGridView.SelectedRows.Count > 0)
            {

                string id = roba_uslugeDataGridView.SelectedRows[0].Cells[0].Value.ToString();
                string sifra = roba_uslugeDataGridView.SelectedRows[0].Cells[1].Value.ToString();
                string naziv = roba_uslugeDataGridView.SelectedRows[0].Cells[2].Value.ToString();

                byte[] ap =(byte[])roba_uslugeDataGridView.SelectedRows[0].Cells["data"].Value;
                MemoryStream ms = new MemoryStream(ap);
                dataPictureBox.Image = System.Drawing.Image.FromStream(ms);
                idTextBox.Text = id;
                sifraTextBox.Text = sifra;
                imeTextBox.Text = naziv;
            }
        }
Goran Bibic8y ago
dataPictureBox.Image = null;

cell name is data
Rafnas T P8y ago
hi,
which cell having image