displaying a image in the datagridview's cell still not solved help!

sachi vasishta

Hi
I have a image called check.jpeg in the resource folder. I have a datagridview which shows some values. Now when I right-click on the dgv I have a option called Checked-in upon clicking on this I want that image check.jpeg to be displyed on that rows third cell. How to do this

Thanks

9 Replies

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Kirtan Patel17y ago
Accepted answer
Hi Sachi ,

Here is What you want . If you don't Under stood the Code I also Included Project Files take a look at them Link is at bottom of the post :)

dont forget to mark "Do you like answer" please it will give me some credits :)

     private void checkToolStripMenuItem_Click(object sender, EventArgs e)
        {
            dataGridView1.CurrentRow.Cells[0].Value = Properties.Resources.check;
        }

        private void uncheckToolStripMenuItem_Click(object sender, EventArgs e)
        {
            dataGridView1.CurrentRow.Cells[0].Value = null;
        }

Download Project Files
Abdou Abdelkbir11y ago
thank you , but when i want to display a lot of images from my folder in datagridview what can i do
Abdou Abdelkbir11y ago
thank you , but when i want to display a lot of images from my folder in datagridview what can i do
bhavana kamble16y ago
thnx for help me to display default page bt i wan display user define image in cell also wan save image at server side with unique name help me for that thing
plz
thanking u;
Kirtan Patel17y ago
Hi Sachi

You can Programatically add Image Column By Following Code

            DataGridViewColumn Imagecolumn = new DataGridViewColumn(new DataGridViewImageCell());
            Imagecolumn.DisplayIndex = 1;
            Imagecolumn.HeaderText = "Image Column";
            dataGridView1.Columns.Add(Imagecolumn);

and You Dont have to Set any Path to Image

Here you can see i Have Check.png Image Named "Check"

So, I just Have to

Write Code Like Below no need to set any path

     private void checkToolStripMenuItem_Click(object sender, EventArgs e)
        {
            dataGridView1.CurrentRow.Cells[1].Value = Properties.Resources.check;
        }
sachi vasishta17y ago
Thanks friend.

I want to know how to have a datagridview's 2nd column as image type (I know I can do it in the properties of dgv but I want to do it by coding) And I have the images in the resource folder of the project. So what path(ImagePath) I have to give in this System.Drawing.Image.FromFile(ImagePath);

Thanks
Hirendra Sisodiya17y ago
hello Sachi
i think you want to show some image on specified datagrid cell. right......
simple you can try if your datagridcell is taken by you as image type :
dataGridView1.Rows[index1].Cells[2].value= System.Drawing.Image.FromFile(ImagePath);
sachi vasishta17y ago
Thanks friend for your kind reply. Nikhil I know all these procedures of making visibility property true/false. But friend what I want is that picturebox/image to be displayed on the dgv's third cell. Let me show you with the code
private void checkedToolStripMenuItem_Click(object sender, EventArgs e)
{
DataGridViewRow row = dataGridView1.CurrentRow;
int index1 = row.Index;
dataGridView1.Rows[index1].Cells[2].value=?????? // what I have to write here in order to display that image(picturebox1)
}

this is my problem
Roei Bar17y ago
hey dude,

have a look @ this post, i belive this is what you are looking for

http://www.codeproject.com/KB/database/DataGridEdtAlmostAnythin.aspx?df=100&forumid=157727&exp=0&select=1058499