FileDialog of C#...

CherRon McLemore

16y4.3k

Hello. I am working on a GUI that will write the contents of a listbox to a text file. After writing the last item, a saveFileDialog pops up. Then you can type in the name of the file and continue to save it to the desired location. My question is how can I access the name of the file I type in to save it to a variable?

Ex. I type in "testerFile" to save as the filename. How do I access that from the dialog textbox to save it to a global string?

5 Replies

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Mahesh Chand16y ago
Accepted answer
fileName = saveFileDialog1.FileName;

http://www.c-sharpcorner.com/UploadFile/mahesh/1878/
CherRon McLemore16y ago
I found from looking at these posts that what I needed was actually the following:

fileName = Path.GetFileName(save.FileName);

Thanks for posting guys!!! :)
Hirendra Sisodiya16y ago
try this code:
private static void saveImage()
{
SaveFileDialog save = new SaveFileDialog();
save.InitialDirectory = Directory.GetCurrentDirectory();
save.Filter = "txt files (*.txt)|*.txt";
if (save.ShowDialog() == DialogResult.OK)
{
string TempfileName = save.FileName; //(whatever I typed into the SaveFileDialog box);
int Index1 = TempfileName.LastIndexOf("\\");
string fileName = TempfileName.Substring(Index1+2, (TempfileName.Length - Index1)-6);
}
}

thanks
please mark as answer if it helps
CherRon McLemore16y ago
I dont think you understand what I am saying.

Ex.
//Global string variable
string fileName;
private static void saveImage()
{
   SaveFileDialog save = new SaveFileDialog();
   save.InitialDirectory = Directory.GetCurrentDirectory();
   save.Filter = "txt files (*.txt)|*.txt";

   if(save.ShowDialog() == DialogResult.OK)
   {
      fileName = (whatever I typed into the SaveFileDialog box);
   }
}

I guess my question is what is the missing code to access what I typed into the savefiledialog box?
Mahesh Chand16y ago
You just need to define either SaveFileDialog control at class level or have a string variable at class level.