How do I generate a random integer in C#?

Question

I want to generate unique random numbers in C#. Once a number is generated, then it must not generate again.

Rajesh Gami · Answer

List listNumbers = new List (); int number; for (int i = 0; i You can create a function and add a min-max value that can generate a random number between those min max values

Sachin Singh · Answer

check this public class RandomNumberGenerator { public Random a = new Random(); public List randomList = new List (); int x= 0; public int GetRandomInt(int min,int max) { x= a.Next(min, max); if (!randomList.Contains(x)) randomList.Add(x); return randomList[x]; } }

Amit Mohanty · Answer

You can use the System.Random class to generate random numbers in C#, and then store the generated numbers in a data structure such as a HashSet to ensure that each number is unique. int totalNumbers = 10; HashSet uniqueNumbers = new HashSet (); Random random = new Random(); while (uniqueNumbers.Count

Jignesh Kumar · Answer

you can use Random calss to generate random int number in various way, Random rnd1 = new Random(); var uniqueNumber = new List (); for (int j = 0; j Note : Next(); has method overloading which will allow you to pass different parameter so you can use according to your requirement.

Vishal Joshi · Answer

Hello Naimish, You can use the Random class to create random numbers. Please check below sample code. Random rnd = new Random(); int month = rnd.Next(1, 13); // creates a number between 1 and 12 Thanks

How do I generate a random integer in C#?

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Answers (5)