How to access content of one page to another page?

Thanks to reply.

plz send me code if is it possible.
Bt i want to access button on next page not textbox.

Use Cross Page Posting,

http://msdn.microsoft.com/en-us/library/ms178139.aspx

Read MSDN Article about Cross page posting.

Use Cross Page posting There are couples of ways of getting control values of the source page into the target page. First way being using FindControl method as discussed below Using FindControl Method In the below listing, we set the PostBackUrl property for Submit button. This property points to the location of the file to which this page should post. In this case, it is DestinationPage.aspx. This means that the DestinationPage.aspx receives the postback and all the values contained in CrossPostingPage.aspx page controls as shown below

This page will cross post to another page by setting PostbackUrl property of submit button.

 
 

SourcePage which does Cross page post back to Destination page You can see in below code how we are able to retrieve values from previous page using FindControl method and display them on Destination Page. Below given output should help you understand the funda. Protected Sub form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles form1.Load Label1.Text = "Name:" + CType(PreviousPage.FindControl("txtName"), TextBox).Text Label2.Text = "Password:" + CType(PreviousPage.FindControl("txtPassword"), TextBox).Text End Sub Output listing Using Control Property Another way of exposing the control values from the Source Page to Destination Page is to create a public property of controls as shown below Public Property UserName() As String Get Return UserName End Get Set(ByVal value As String) End Set End Property Public Property Password() As String Get Return Password End Get Set(ByVal value As String) End Set End Property In order to work with the properties described in FindControl page as shown above, PreviousPageType directive should be included in the destination page that is in DestinationPage.aspx. See below listing <%@ PreviousPageType VirtualPath="FindControl.aspx"%> The above directive points to FindControl.aspx by specifying the VirtualPath attribute and when that is in place, one can see the properties exposed by FindControl page in DestinationPage using the PreviousPage property. It is always better to expose only the information we need as public properties to reduce the amount of information available to potentially malicious users. IsCrossPagePostBack Property IsCrossPostBack property, which is new in ASP.NET 2.0, enables us to check whether the page is participating in a cross page request. Using IsCrossPostBack property, we can check whether the request is coming from a particular page or not and act accordingly. As per above example, DestinationPage can include this property to specially process the FindControl.aspx cross page post back. Similarly, we can use the IsValid property of our previous page to make sure the page passed all client validations before it is cross posted to DestinationPage. If Page.IsCrossPagePostBack Then Label1.Text = "Name:" + CType(PreviousPage.FindControl("txtName"), TextBox).Text Label2.Text = "Password:" + CType(PreviousPage.FindControl("txtPassword"), TextBox).Text Else Label1.Text = "No Name:Normal Postback" Label2.Text = "No password: normal postback" End If Hence, Cross Page posting is very handy feature to implement very specific scenarios like displaying logged in user details on different pages and ensuring the request is coming from correct page. You can implement this feature in either two ways using FindControl method or exposing values as public properties. PreviousPage object will expose very useful properties like IsValid property and FindControl property to make Cross Page Posting more useful.