How to find the angle between hour and minute hands of a clock ?

Hi Guest User,

One can find the angle between hour and minute hands of a clock in C# as following:

int h=2, m=20;

double angle = (System.Math.Abs(((60*h-11*m)/2.0)) > 180) ? (360 - System.Math.Abs(((60*h-11*m)/2.0))) : (System.Math.Abs(((60*h-11*m)/2.0)));

Console.WriteLine(angle);

For more details:

https://en.wikipedia.org/wiki/Clock_angle_problem

Hope, this will help you!

public int getAngle(int Hours,int Minutes)
        {
            return Math.Abs(Hours-Minutes)*30;
        }

// C# program to find the angle between
// hour and minute hands
using System;

class Angle {
	
	// Function to calculate the angle
	static int calcAngle(double h, double m)
	{
		// validate the input
		if (h < 0 || m < 0 ||
			h > 12 || m > 60)
			Console.Write("Wrong input");

		if (h == 12)
			h = 0;
			
	if (m == 60)
	{
		m = 0;
		h += 1;
		if(h>12)
		h = h-12;
	}

		// Calculate the angles moved by hour and
		// minute hands with reference to 12:00
		int hour_angle = (int)(0.5 * (h * 60 + m));
		int minute_angle = (int)(6 * m);

		// Find the difference between two angles
		int angle = Math.Abs(hour_angle - minute_angle);

		// smaller angle of two possible angles
		angle = Math.Min(360 - angle, angle);

		return angle;
	}
	
	// Driver code
	public static void Main ()
	{
		Console.WriteLine(calcAngle(9, 60));
		Console.Write(calcAngle(3, 30));
	}
}

// Output 
60
75