how to generate popup click on submit button in asp.net

Anjali Khan

8y4.4k.NET

Hi Frnds

I have a page with registration form.when i submit the data it is showing succesfully and it save in data base .

now i want when i click on submit button i want popup with message successfully.

i am using application with asp.net .

this is my button

asp:Button ID="btnSubmit" runat="server" Text="Generate" ValidationGroup="Diary" CssClass="btn btn-primary"

OnClick="btnSubmit_Click" ToolTip="Click To Save" />

8 Replies

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Laxmidhar Sahoo8y ago
hi
Please give the brake point in the start of the function .there are some exceptions
inthe the code.find out the exception poin or line and if is there any variable then
define in the top of the function and the exception line should be taken in the try catch

and the take message code out of the try catch block
Anjali Khan8y ago
Hi Laxmidher

below the namespace which i used my page

using System;
using System.Configuration;
using System.Data;
using System.Globalization;
using System.IO;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
Anjali Khan8y ago
Ok Laxmidhet I will check my code and share with you shortly
Bryian Tan8y ago
I think the suggestion from @Laxmidhar Sahoo should work. What the error you getting?
Laxmidhar Sahoo8y ago
Hi
I am asking about the namespace those are in the top
like
using system;
using system.Data;

Please display the all the above the namespace used in that page
Laxmidhar Sahoo8y ago
hello
Please show me the namespaces added in the top of the page
is function InsertDiary(); type is void ?
Anjali Khan8y ago
Hi Laxmidhar
thanks for the update.

ut this code not working . see my

protected void btnSubmit_Click(object sender, EventArgs e)
{
if (Page.IsValid)
{
InsertDiary();
// Page.ClientScript.RegisterStartupScript(this.GetType(), "scriptsKey", "");
}
}
Laxmidhar Sahoo8y ago
in code behind in the btnSubmit_Click() function put the the code like

btnSubmit_Click()
{
/ your saved code
Page.ClientScript.RegisterStartupScript(this.GetType(),"scriptsKey","");
}