Loading

How to get duplicate elements with count then unic elements

How to get duplicate elements with count then unic elements

Prashant MD

How to get duplicate elements with count then unic elements X=[`hello', 'cricket','bye','hello','bye']

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Rajanikant Hawaldar6y ago
Accepted answer
I have used Counter class of collections module, it is a container that tracks how many times equivalent values are added and stores elements as dictionary keys, and their counts are stored as dictionary values.
import collections
X=['hello','cricket','bye','hello','bye']
print(collections.Counter(X))
+1
Sachin Singh6y ago
//  c#
ar Unique=x.Select(x => x.ToLower()).Distinct<string>()
   int UniqueCount=Unique.Length;

  int nonUniqueCount=x.Length;
//  Python
  def unique(list1):

      # intilize a null list
      unique_list = []

      # traverse for all elements
      for x in list1:
          # check if exists in unique_list or not
          if x not in unique_list:
              unique_list.append(x)
      # print list
      for x in unique_list:
          print x,



  # driver code
  list1 = [10, 20, 10, 30, 40, 40]
  print("the unique values from 1st list is")
  unique(list1)
  //count:-
print(len(unique(list1)))


  list2 =[1, 2, 1, 1, 3, 4, 3, 3, 5]
  print("\nthe unique values from 2nd list is")
  unique(list2)
  //count:-
print(len(unique(list2)))
0