How to get duplicate elements with count then unic elements

Question

How to get duplicate elements with count then unic elements X=[`hello', 'cricket','bye','hello','bye']

Rajanikant Hawaldar · Answer

I have used Counter class of collections module, it is a container that tracks how many times equivalent values are added and stores elements as dictionary keys, and their counts are stored as dictionary values. import collections X=[ 'hello' , 'cricket' , 'bye' , 'hello' , 'bye' ] print (collections.Counter(X))

Sachin Singh · Answer

// c# ar Unique=x.Select(x => x.ToLower()).Distinct string >() int UniqueCount=Unique.Length; int nonUniqueCount=x.Length; // Python def unique(list1): # intilize a null list unique_list = [] # traverse for all elements for x in list1: # check if exists in unique_list or not if x not in unique_list: unique_list.append(x) # print list for x in unique_list: print x, # driver code list1 = [10, 20, 10, 30, 40, 40] print( "the unique values from 1st list is" ) unique(list1) //count:- print(len(unique(list1))) list2 =[1, 2, 1, 1, 3, 4, 3, 3, 5] print( "
the unique values from 2nd list is" ) unique(list2) //count:- print(len(unique(list2)))

How to get duplicate elements with count then unic elements

Answers (2)