How to get full path of selected file from OpenFileDialog ?

Sachin Kadam

15y27kC#

hi,

i want to get path of selected file using OpenFileDialog,
but its shown "File operation not permitted. Access to path is denied." error.

I have user following code and want to display full path in text box

OpenFileDialog dlg = new OpenFileDialog();
dlg.Multiselect = false;dlg.Filter = "Video Files (*.mp4)|*.mp4|Video Files (*.mpeg)|*.mpeg|Video Files (*.wmv)|*.wmv";
dlg.FilterIndex = 1;
bool? retval = dlg.ShowDialog();
if (retval != null && retval == true)
{
UploadVideo(dlg.File.Name, dlg.File.OpenRead());
//string filePath = Path.GetDirectoryName(dlg.File.Name);
txtVideoPath.Text = dlg.File.Name;
}

Any idea how to get full path?

4 Replies

Know the answer? Post it — somebody with the same question will find it here.

Marutharasu P12y ago
OpenFileDialog ofd = new OpenFileDialog(); if((bool)ofd.ShowDialog()) { string directoryName = ofd.File.DirectoryName; string fullName = ofd.File.FullName; string name = ofd.File.Name; }
Vulpes14y ago
For security reasons it will only work in 'trusted applications', but you should be able to get the full path with:

txtVideoPath.Text = dlg.File.FullName;
ravi rayana14y ago
Hi Prabhu, This is not System.Windows.Forms.OpenFileDialog this is System.Windows.Controls.OpenFileDialog. Here we do not have RestoreDirectory & FileName properties.
Prabhu Raja15y ago
Hi Sachin,

Try this

OpenFileDialog dlg = new OpenFileDialog();
dlg.Multiselect = false;
dlg.InitialDirectory = "C:\\";
dlg.Filter = "Video Files (*.mp4)|*.mp4|Video Files (*.mpeg)|*.mpeg|Video Files (*.wmv)|*.wmv";
dlg.FilterIndex = 0;
dlg.RestoreDirectory = true;
if (dlg.ShowDialog() == DialogResult.OK)
{
try
{
UploadVideo(dlg.FileName, dlg.OpenFile );
txtVideoPath.Text = dlg.FileName;
}
catch (Exception ex)
{
MessageBox.Show("Error: can not read file from disk.Original error: " + ex.Message);
}
}

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