How to open a model window on click on any row of datagrid?

function OnMenuMouseOver(obj)
            {
           
            obj.style.cursor='hand';
            }

call this javascript function on itemdatabound event.

public void dgrdExhibitorInfo_ItemDataBound(object sender, System.Web.UI.WebControls.DataGridItemEventArgs e)
    {
        if (e.Item.ItemType == ListItemType.AlternatingItem ||
            e.Item.ItemType == ListItemType.Item)
        {
           
            e.Item.Attributes.Add("onclick", "OpenWin(this)");
            e.Item.Attributes.Add("onmouseover", "OnMenuMouseOver(this)");

        }
    }
 

You can use the datagrid item databound event to accomplish this tusk. Inside item databound event you can call
the java script function to open the page.