How to open file location from list view item using context menu strip?

Here is list of things I want to do:
Display context menu  strip only when mouse is over the item and right clicked on it, the code I have for that is this:

        private void contextMenuStrip1_Opening(object sender, CancelEventArgs e)

        {

            if (listView1.SelectedItems.Count == 0)

                e.Cancel = true;

        }

        private void contextMenuStrip1_MouseClick(object sender, MouseEventArgs e)

        {

            if (e.Button == MouseButtons.Right)

            {

                Point pt = listView1.PointToScreen(e.Location);

                contextMenuStrip1.Show(pt);

            }

        }

The problem about this code is longest the item is selected it will display the menu strip, what I don't want is the context menu strip shouldn't show up unless directly right clicked on the item.
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I have 3 options on the context menu strip, open, open file location and properties. If user right clicks the item and says open, its should ask the user what do you want to open it with using Windows explorer! For the open file location, I came up with this:

Process.Start("explorer.exe", "I need filepath from listview item");

That does open the custom location, however since there is going to be lots of files in the list view, I need the program to get the file location it self.

The implementation I have for the scanning files and displaying them on list view is:


Hope that can help you a bit, if you need to know more ask, I also have a code to calculate the size of the file, i didn't insert is because I don't think you will need it really. If anything is not clear plz do ask and thank you very much all helps are appreciated.