mathematical euation

sorry sorry its working am absent minded.so thank u again

For 1000 at 18% per annum convertible quarterly for 10 years, the program gives 5816.36.

My scientific calculator gives exactly the same answer:

1000 x 1.045 ^ 40 = 5816.36

So, I'm sure the program is working correctly. 

protected void txt_installmentamt_TextChanged(object sender, EventArgs e)
    {
        double p = Double.Parse(txt_installmentamt.Text);
        double r =(Double.Parse(lbl_rtofintr.Text)/100);
        int n = 4; // quarterly
        int t =int.Parse(lbl_tenure.Text);
        double A = AccumulatedValue(p, r, n, t);      
        lbl_depamt.Text = (Double.Parse(txt_installmentamt.Text)).ToString("#0.00");
        lbl_returns.Text =  A.ToString("#0.00");
     
    }

    protected  double AccumulatedValue(double p, double r, int n, int t)
    {
        return p * Math.Pow(1 + r / n, n * t);
    }

u give me this code and it only working for one year more than one year it show wrong information
plz help me

If you click on my user name there's an option to send me a message.

However, as a general rule, I only answer questions on the forum itself.

I just tried it myself for 100 per month with the following results:

9%    =  1259.68
18%  =   1321.77

My scientific calculator gives exactly the same results.

The calculator on this site:

http://easycalculation.com/finance/recurring-deposits-maturity-value.php

gives the following answers:

9%    =  1257.91 
18%  =  1321.34

Not quite the same - possibly due to rounding errors.

What do you get?

double R = Double.Parse(txt_installmentamt.Text);
        double i = (Double.Parse(lbl_rtofintr.Text)/400);
        //int n =int.Parse( lbl_tenure.Text);
        int n = 4;
        double M = R * (Math.Pow(1 + i, n) - 1) / (1 - Math.Pow(1 + i, -1.0 / 3.0));
        lbl_returns.Text = M.ToString("#0.00");
        lbl_depamt.Text = (Double.Parse(txt_installmentamt.Text) * Double.Parse(lbl_tenure.Text)).ToString("#0.00");
i have got the correct answer when am calculate intest on 9% but it fails to give correct answer when am using 18%intrest

first of thans for helping i just given my source code u just help me to find out recurring deposite formulla
 //txt_insta=installment amount
double R = Double.Parse(txt_installmentamt.Text);
 //lbl_rtofint=rate of intrest
 double i = (Double.Parse(lbl_rtofintr.Text)/400);
//lbl_tenure=how much time he wiil givemeans for 12 month or 24 etc
 int n =int.Parse( lbl_tenure.Text);
 double M = R * (Math.Pow(1 + i, n) - 1) / (1 - Math.Pow(1 + i, -1.0 / 3.0));
 lbl_returns.Text = M.ToString("#0.00");
 lbl_depamt.Text = (Double.Parse(txt_installmentamt.Text) * Double.Parse(lbl_tenure.Text)).ToString("#0.00");

You can write that particular formula in C# as follows:

double M = R * (Math.Pow(1 + i, n) - 1)/ (1 - Math.Pow(1 + i, -1.0/3.0)); 

Hi...

Did not get - plz tell me the calclation of recurring deposite

Try: