Open with.. C# problem

When you try to open your program with (open with at some file), you pass two arguments to your program.

1-st one is path of your program, and 2-nd is path of that file...
So what you have to do is to make Open metod.. something like this:

public void Open (string path)

{

ritchTextBox.LoadFile(path);// and when you call that metod you will pass that second argument( path of that .txt file)

}

and in onLoad event call that metod something like this:

string path = Environment.GetCommandLineArgs()[1]

Open(path);