Opening files

mithil Malhotra

16y4.1k

Hiiii

Anyone would suggest me when i open a file and cilck ok button it should open in seperate dialog box. Here when i am clicking on open button, the dialog box appears. I selected a particular file, while opening the file its showing the path name in text box i gave to my form.

This i am using to open a file dialog, and selecting the file which is showing it into the textbox.

Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
        If OpenFileDialog1.ShowDialog() <> Windows.Forms.DialogResult.Cancel Then
            TextBox1.Text = OpenFileDialog1.FileName
        End If
    End Sub

But when i click on open buttons next to textbox, that file should open which i have selected. Here is the Image of that.

Would anyone suggest me how to write the code for that.

Regard
Mithil

3 Replies

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Albertto Lie16y ago
Accepted answer
hi..
maybe this help
1st u have to add some code
using System.Diagnostics;

then add some other code to your button event
Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
If OpenFileDialog1.ShowDialog() <> Windows.Forms.DialogResult.Cancel Then
TextBox1.Text = OpenFileDialog1.FileName
```
         Process.Start(OpenFileDialog1.FileName)
```
End If
End Sub
mithil Malhotra16y ago
Hiiii

I have made Menustrip with menu File
Please suggest me the code for that........

Thanks and Regard
Mithil
mithil Malhotra16y ago
hiiii Albert

Thanks, it helped me as i go one step further doing my project work.