PerformClick not working for second time

kris sarma

I have a dialog with a button.

Somewhere in another page, I am launching the dialog and registering Load event and firing the button click using button.PerformClick

This works fine when I create instance of dialog every time where i am planning to call. but if I reuse the dialog, second time onwards the button click event is not firing

public partial class dlg : Form

{ // button1 is public

public dlg() { InitializeComponent(); }

private void button1_Click(object sender, EventArgs e) { MessageBox.Show("XXX"); }

}

-------------

dlg d = new dlg(); // option 1

void Test()

{

// dlg d = new dlg(); // option 2

d.Load += new EventHandler(delegate(object a, EventArgs ty) { d.button1.PerformClick(); });

d.ShowDialog();

}

If I enable option 2, I would get message "XXX" each time i call the Test method. If I enable option 1, first time it popups the message and not for the consequent times.

4 Replies

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kris sarma14y ago
This is what the Option 2 referred to in my sample, I guess. This works all the times, since each time we are creating a fresh dialog/form and performing against to that. Logically it refers to performing first time in that form instance. But what I was referring in option 1 is, the form/dialog instance is not created on every click. instead uses same form instance. Here in our application those forms are preseved in flyweight object and hence we cannot create fresh form instances again and again. Hence I need to get the event to be fired again and again on the same instance of dialog. Hope this clears the confusion with the requirement.
Frogleg14y ago
public partial class Form1 : Form
    {

        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }

        private void button1_Click(object sender, EventArgs e)
        {

            Test();

        }

        void Test()
        {

            Form2 f2 = new Form2();

            f2.Load += new EventHandler(delegate(object a, EventArgs ty) { f2.button1.PerformClick(); });

            f2.ShowDialog();

        }

this works every time
kris sarma14y ago
Unfortunately I cannot do this as I donot own the code of dlg. The only possibility is to identify the button object (using reflection) and to perform the click action of it. Infact my question is why the event is not firing with option 1 and how to make event to fire in case of any limitation.
Frogleg14y ago
Just put the code within the button click code into it's own method

private void button1_Click(object sender, EventArgs e)
        {
            doWhatever();
        }

private void button2_Click(object sender, EventArgs e)
         {
             doWhatever();
         }

public void doWhatever()
    {
    messageBox.Show("whatever");
    }