Please help in preparing xml file from another raw xml file using C#.net programmatically

chiru ommi

Hi

Please help in preparing the xml dynamically ( programmatically) from another raw xml file( input file)

my raw xml file is as below

******************************************

JTEST5
user_16.png

Application
files_16.png

Document Correspondence - gm22_1.gif
2011-11-24 03:48:14.677407O01
5
EFSDOC
document_16.png

Approval Form
files_16.png

Document tes - Index.JPG
2012-01-17 05:24:04.360768O01
6
EFSDOC
document_16.png

INSURANCE
FPCD

***************************************

Now my new xml file is below (more this is need to be prepare programmaticlly using C#.net)

Hence please help out in this

Thanks in advance

Thanks
Chiranjeevi

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes14y ago
Accepted answer
Try this:

using System;
using System.Xml.Linq;

class Program
{
static void Main()
{
XElement xe = XElement.Load("chiru.xml");

XElement browse = new XElement("browse");
XElement user = new XElement("user",
new XAttribute("text", xe.Element("efsName").Value),
new XAttribute("icon", xe.Element("icon").Value));

foreach(XElement fe in xe.Element("folders").Elements("folder"))
{

XElement folder = new XElement("folder",
new XAttribute("text", fe.Element("folderName").Value),
new XAttribute("icon", fe.Element("foldericon").Value));

XElement se = fe.Element("source");

XElement source = new XElement("source",
new XAttribute("text", se.Element("sourceName").Value),
new XAttribute("sourceId", se.Element("sourceId").Value),
new XAttribute("key", se.Element("key").Value),
new XAttribute("sourceType", se.Element("sourceType").Value),
new XAttribute("icon", se.Element("sourceIcon").Value));

folder.Add(source);
user.Add(folder);
}

browse.Add(user);
browse.Save("chiru2.xml");
}
}
chiru ommi14y ago
hi

thank Q for giving your help, your code is working fine

Thanks
Chiranjeevi Yadav