program to generate N random numbers between any two specifi

Question

program to generate N Random Numbers between any two specified numbers 2.accept anumber and print its binary and hexadecimal 3. convert ASCII value to its equivalent character

Vulpes · Answer

And here's a program to generate the random numbers; using System; class Program { static Random rand = new Random(); static void Main() { Console.Write("Enter N : "); int N = int.Parse(Console.ReadLine()); Console.Write("Enter first number : "); int a = int.Parse(Console.ReadLine()); Console.Write("Enter last number : "); int b = int.Parse(Console.ReadLine()); Console.WriteLine("{0} random numbers between {1} and {2} are
", N, a, b); for(int i = 0; i { Console.Write("{0} ", rand.Next(a, b + 1)); } Console.ReadKey(); } }

Sanjeeb Lenka · Answer

From integer to hex and binary: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Class1 { static void Main(string[] args) { Console.WriteLine("Enter a number to get its binary and hex equivalent"); // create some examples int no = Convert.ToInt32(Console.ReadLine()); string binary = Convert.ToString(no, 2); string myHex = no.ToString("X"); // gives you hex Console.WriteLine("Binary: {0}",binary); Console.WriteLine("Hex: {0}", myHex); Console.ReadKey(); } } } ASCII to char: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Class1 { static void Main(string[] args) { Console.WriteLine("Enter ASCII value to get the char"); // create some examples int ASCII = Convert.ToInt32(Console.ReadLine()); // Cast to Char - display an integer as its ASCII value - 69 = E Console.WriteLine((Char)ASCII); // or use the convert method Console.WriteLine(Convert.ToChar(ASCII)); Console.ReadKey(); } } }

program to generate N random numbers between any two specifi

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