Random.next.....

Hello

You are accessing next method in wrong way

For that you should create class with new keyword like below :

I have shown below the complete working demo for this :

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
namespace RandomDemo
{
public class Program
{
public static void Main(string[] args)
{
Random randomNumbers= new Random();
// Generates random number from next 10 digits
int intValues1 = randomNumbers.Next(10);
// Generates random number between 1 to 100
int intValues2 = randomNumbers.Next(1, 100); // creates a number between 1 and 6
Console.WriteLine("Next Random from 10 values :-" + intValues1);
Console.WriteLine("Random from 1 to 100 is :-" + intValues2);
}
}
}

Output will be :

Next Random from 10 values :-5

Random from 1 to 100 is :-55

So you can use both next() with single int value or range of values

I hope now you got my point

Thanks

2 Replies

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Manav Pandya8y ago
Accepted answer
Hello

You are accessing next method in wrong way

For that you should create class with new keyword like below :
Random randomValues = new Random();

// now you can use next method by using object randomValues
I have shown below the complete working demo for this :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

namespace RandomDemo
{
    public class Program
    {
        public static void Main(string[] args)
        {
           Random randomNumbers= new Random();

           // Generates random number from next 10 digits
            int intValues1 =  randomNumbers.Next(10);

           // Generates random number between 1 to 100
            int intValues2 =  randomNumbers.Next(1, 100);   // creates a number between 1 and 6

            Console.WriteLine("Next Random from 10 values :-" + intValues1);

            Console.WriteLine("Random from 1 to 100 is :-" + intValues2);

        }
    }
}
Output will be :
Next Random from 10 values :-5
Random from 1 to 100 is :-55

So you can use both next() with single int value or range of values

I hope now you got my point

Thanks
0
Jaish Mathews8y ago
You have your own Random.cs, which is supressing C# bult-in Random class and so .Next is not appearing as in your Random class you didn't define any Next method. Either your class or built-in class to use, not both.
0