Random.next.....

Question

I am trying to call the method next from the random claoss. but it is not appearing in the list. attached the slide. pls check and let me know.

Manav Pandya · Answer

Hello You are accessing next method in wrong way For that you should create class with new keyword like below : Random randomValues = new Random(); // now you can use next method by using object randomValues I have shown below the complete working demo for this : using System; using System.Collections.Generic; using System.Linq; using System.Text.RegularExpressions; namespace RandomDemo { public class Program { public static void Main(string[] args) { Random randomNumbers= new Random(); // Generates random number from next 10 digits int intValues1 = randomNumbers.Next(10); // Generates random number between 1 to 100 int intValues2 = randomNumbers.Next(1, 100); // creates a number between 1 and 6 Console.WriteLine( "Next Random from 10 values :-" + intValues1); Console.WriteLine( "Random from 1 to 100 is :-" + intValues2); } } } Output will be : Next Random from 10 values :-5 Random from 1 to 100 is :-55 So you can use both next() with single int value or range of values I hope now you got my point Thanks

Jaish Mathews · Answer

You have your own Random.cs, which is supressing C# bult-in Random class and so .Next is not appearing as in your Random class you didn't define any Next method. Either your class or built-in class to use, not both.

Random.next.....

Answers (2)