Reference array char* in C

Unlike C++, C doesn't support passing parameters by reference, only by value. However, you can simulate this by passing a pointer a value and, since an array is already a pointer, a function can change the elements of the array using the pointer and these changes will be persisted to the caller:

void refarray(char *arraybuff[])
{
  char *s1="hello";
  char *s2="everybody";
  arraybuff[0]=s1;
  arraybuff[1]=s2;
}
void main()
{
  char *getarray[2];
  refarray(getarray);
  printf("%s %s",getarray[0],getarray[1]);
}

As expected, the output is:

hello everybody