Regular Expression in next type

jithendra pasala

Hello All,

I want to break the string by using the Regular Expression:

String1:"((G011, (G012 + !(111_HIGH_SECURITY))) + !(ALLRAD) + (B48B20, XB1141) + OL + (PLUGIN_HYBRID))"

Output:
(G011 + !(ALLRAD) + B48B20 + OL + (PLUGIN_HYBRID))

(G011 + !(ALLRAD) + XB1141+ OL + (PLUGIN_HYBRID))

(G012 + !(111_HIGH_SECURITY)+ !(ALLRAD) + B48B20 + OL + (PLUGIN_HYBRID))

(G012 + !(111_HIGH_SECURITY)+ !(ALLRAD) + XB1141+ OL + (PLUGIN_HYBRID))

String2:"((G011, (G012 + !(111_HIGH_SECURITY))) + (KEIN_HYBRID))"

Output:
(G011 + (KEIN_HYBRID))

(G011 + !(111_HIGH_SECURITY) + (KEIN_HYBRID))

One Regular Expression should server for both the strings.

Thanks in Advance

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes12y ago
Accepted answer
OK, jithendra, try this new regular expression:

using System;
using System.Text.RegularExpressions;

class Test
{
static void Main()
{
string[] inputs =
{
"((G011, (G012 + !(111_HIGH_SECURITY))) + !(ALLRAD) + (B48B20, XB1141) + OL + (PLUGIN_HYBRID))",
"((G011, (G012 + !(111_HIGH_SECURITY))) + (KEIN_HYBRID))",
"((G011, (G012 + !(111_HIGH_SECURITY))) + ALLRAD + (N63B40, N63B44) + OL)"
};
string re = @"^$(\(.*?$)\)\)((.*?)$(\w+,.*?)$)?(.*)$";

foreach(string input in inputs)
{
Match m = Regex.Match(input, re);

string[] split1 = Regex.Split(m.Groups[1].Value, @",\s*");
string str3 = m.Groups[3].Value;
string[] split2 = Regex.Split(m.Groups[4].Value, @",\s*");
string str4 = m.Groups[5].Value;

foreach(string s1 in split1)
{
foreach(string s2 in split2)
{
Console.WriteLine("{0}{1}{2}{3}", s1, str3, s2, str4);
}
}

Console.WriteLine();
}

Console.ReadKey();
}
}

The output now is:

(G011 + !(ALLRAD) + B48B20 + OL + (PLUGIN_HYBRID))
(G011 + !(ALLRAD) + XB1141 + OL + (PLUGIN_HYBRID))
(G012 + !(111_HIGH_SECURITY) + !(ALLRAD) + B48B20 + OL + (PLUGIN_HYBRID))
(G012 + !(111_HIGH_SECURITY) + !(ALLRAD) + XB1141 + OL + (PLUGIN_HYBRID))

(G011 + (KEIN_HYBRID))
(G012 + !(111_HIGH_SECURITY) + (KEIN_HYBRID))

(G011 + ALLRAD + N63B40 + OL)
(G011 + ALLRAD + N63B44 + OL)
(G012 + !(111_HIGH_SECURITY) + ALLRAD + N63B40 + OL)
(G012 + !(111_HIGH_SECURITY) + ALLRAD + N63B44 + OL)
jithendra pasala12y ago
Hi Vulpes,

The given solution of regular expression not working for

((G011, (G012 + !(111_HIGH_SECURITY))) + ALLRAD + (N63B40, N63B44) + OL)

that should work for above string also

pls help
Vulpes12y ago
Try the following.

For String 2 I've assumed that the second output string should read:

(G012 + !(111_HIGH_SECURITY) + (KEIN_HYBRID))

using System;
using System.Text.RegularExpressions;

class Test
{
static void Main()
{
string[] inputs =
{
"((G011, (G012 + !(111_HIGH_SECURITY))) + !(ALLRAD) + (B48B20, XB1141) + OL + (PLUGIN_HYBRID))",
"((G011, (G012 + !(111_HIGH_SECURITY))) + (KEIN_HYBRID))"
};
string re = @"^$(\(.*?$)\)\)((.*?\)\s*\+\s*)$(.*?)$)?(.*)$";

foreach(string input in inputs)
{
Match m = Regex.Match(input, re);

string[] split1 = Regex.Split(m.Groups[1].Value, @",\s*");
string str3 = m.Groups[3].Value;
string[] split2 = Regex.Split(m.Groups[4].Value, @",\s*");
string str4 = m.Groups[5].Value;

foreach(string s1 in split1)
{
foreach(string s2 in split2)
{
Console.WriteLine("{0}{1}{2}{3}", s1, str3, s2, str4);
}
}

Console.WriteLine();
}

Console.ReadKey();
}
}