Scenairo - Print odd numbers from user input number.

anoop kumar

8y2kVisual Basic .NET

class Program

{

static void Main(string[] args)

{

int regen, result;

Console.WriteLine("Enter the Number");

int getnum = Convert.ToInt32(Console.ReadLine());

while (getnum > 0)

{

regen = getnum % 10;

result = regen;

getnum = getnum / 10;

if (result % 2 != 0)

{

Console.WriteLine("These are the Odd Numbers" + result);

}

Console.ReadKey();

}

9 Replies

Know the answer? Post it — somebody with the same question will find it here.

Tapan Patel8y ago
Accepted answer
The solution I provided had me thinking .
Actually, you can solve this issue via string manipulation as well.

Meaning, instead of converting each character (digit) to int counter part and then checking if number is odd or even, you can store the even digits in string and do something like this:
string number = "3455543234232177666";
string evens = "24680";

foreach (char digit in evens)
{
    number = number.Replace(digit.ToString(), string.Empty);
}
Console.WriteLine(number);
Rafnas T P8y ago
hi,
try below code for getting all the odd nombers from your input nombers
using System;

public class Program
{
    public static void Main()
    {
         string result,getnum;
         Console.WriteLine("Enter the Number");
         getnum =Console.ReadLine();

        while (getnum.Length > 0)
        {
            result = getnum.Substring(0,1).ToString();
            if (Convert.ToInt32(result) % 2 != 0)
            {
            Console.WriteLine("These are the Odd Numbers" + result);
            }
            if(getnum.Length==1)
            {
                getnum="";
            }
            else if(getnum.Length>1)
            {
            getnum=getnum.Substring(1,getnum.Length-1).ToString();
            }
         }

    }
}
Tapan Patel8y ago
1. string number = "3455543234232177666";
2. foreach (char digit in number)
3. {
4. Console.Write((digit - '0') % 2 != 0?digit.ToString():string.Empty);
5. }
6. Console.WriteLine();
No Linq

anoop kumar8y ago

Tapan Patel

Thanks but can you provide solution without LINQ.

Tapan Patel8y ago

If you have liberty to use Linq, you can do something as below:

string number = "3455543234232177666";
Console.WriteLine(new string(number.Where(x=>(x-'0')%2!=0).ToArray()));

anoop kumar8y ago

Sai Kumar Koona

Thanks for replying........but my question was different. I had asked that " print only those odd number which is available in input number" eg - if I put 7845125895. then output should be - 751595.

Sai Kumar Koona8y ago

Please find the below code which will print all the odd numbers which are eligible till the given number.

Console.WriteLine("Enter the Number");
int n1 = Convert.ToInt32(Console.ReadLine());
for (int n = 1; n < (n1 + 1); n++)
{
if (n % 2 != 0)
{
Console.WriteLine(n.ToString());
}
}

anoop kumar8y ago

Pushkar Pushp

2. print only those odd number which is avliable in input number

Pushkar Pushp8y ago

Let me confirm :-

1. Odd number from 1 to enterd number OR

2. print only those odd number which is avliable in input number