Split and sum array element like below.

Pruthvi Patel

arr[]={1,3,2,4,6,7,8,8};

split=2; // the arr[] will be divide in 2(no of splits) parts each with equal elements

skip=1; // skip is no of element to be skipped.

size of res[] should be accordingly.

then

res[0]=3 //1+2

res[1]=7 //3+4

res[2]=14 //6+8

res[3]=15 //7+8

split=1,2,3...n

skip=1,2,3...n

arr[]={1,2,3...n} elements

This should be dynamically.

Please help me to do this.

Thanks

5 Replies

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Manas Mohapatra9y ago
Accepted answer
Try with below code:
int[] arr = { 1, 3, 2, 4, 6, 7, 8, 8 };
int split = 2;
int counter1 = 0;
int counter = arr.Length / (split);
int[] tempArr = new int[counter];

for (int idx = 0; idx < counter; idx++)
{
    if (idx % split == 0)
    {
        counter1 = idx * split;
    }
    else
    {
        counter1 = idx * split - 1;
    }

    tempArr[idx] = arr[counter1] + arr[counter1 + split];
}
Pruthvi Patel9y ago
Hi manas,
Please help me in this. In above code there is skip=1 only. but if i am want to change it then how to do this?
arr[]={1,2,3,4,5,6,7,8,9,10,11,12,8,9,6,5,4,2}
split=3
skip=2
res1[0]= 5 //1+4
res1[1]=7 //2+5
res1[2]=9 //6+3
res1[3]=17 //7+10
res1[4]=19 //8+11
res1[5]=21 //12+9
res1[6]=13 //8+5
res1[7]=13 //9+4
res1[8]=8 //6+2

Like this where skip and split can be 1,2,3..n

Please Please Help me to do this as i have to use this in my college project work.Please
Pruthvi Patel9y ago
Hi,Manas
In above requirement skip=1 but if i want to change it then how to do this.
Please help me to do this
Manas Mohapatra9y ago
Updated previous answer, please check..
Pruthvi Patel9y ago
ManasThanks help
can you use the variable(split,skip) in this code.So i can able to change accordingly my requirement.