Uncaught TypeError: Cannot read property 'substr' of undefin

Iam getting this jquery error

"Uncaught TypeError: Cannot read property 'substr' of undefind"

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function FunctionRetunrSave(jsondata) {

debugger;

$('#<%= TrGrid.ClientID %>').show();

// $("#list1").jqGrid("clearGridData", true);

-------

$(document).ready(function() { -- iam getting that error on this line

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var lastsel2;

jQuery("#list1").jqGrid({

datatype: "local",

colNames: ['StockistCode', 'StockistName', 'DIVISION_NAME'],

colModel: [

{ name: 'StockistCode', index: 'StockistCode', width: 500 },

{ name: 'StockistName', index: 'StockistName', width: 500 },

{ name: 'DIVISION_NAME', index: 'DIVISION_NAME', width: 500 },

pager: jQuery('#pager1'),

sortable: false,

viewrecords: true,

caption: "Query List",

width: 1100

}).navGrid(pager, { edit: false, add: true, del: false, refresh: true, search: false });

var mydata;

var thegrid = jQuery("#list1")[0];

if (jsondata != null) {

thegrid.addJSONData(JSON.parse(jsondata.responseText).d);

mydata = JSON.parse(jsondata.responseText).d;

}

var $grid = $("#list1");

for (var i = 0; i <= mydata.length; i++) {

jQuery("#list1").jqGrid('addRowData', i + 1, mydata[i]);

}

});

}

How to resolve this error ,Please do need full to me

2 Replies

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Bikesh Srivastava9y ago
check object is undefined and then use substr.
Alessandro Sperone9y ago
You are passing an undefined value with jquery. You can simply test every value taken with the jquery selector (use console.log for that) and find the undefined one.