Unique Index

Question

Hi I have unique Index on Student field in Database sql. I want when Unique Index error comes , i want to display my own error 'Duplicate record found' Thanks

Vishal Yelve · Answer

Hi Ramco, try this if(ex.Message.Contains("UNIQUE KEY constraint")) { // your message }

Tuhin Paul · Answer

You can also include the custom error message in a THROW statement BEGIN TRY INSERT INTO Students (StudentID, Name, Age) VALUES (123, 'John Doe', 25); END TRY BEGIN CATCH IF ERROR_NUMBER() = 2601 BEGIN THROW 50000, 'Duplicate record found', 1; END END CATCH

Tuhin Paul · Answer

Lets say you have a table named Students with a unique index on the StudentID field. You can catch the unique index violation error using a TRY...CATCH block in your SQL query like this BEGIN TRY INSERT INTO Students (StudentID, Name, Age) VALUES (123, 'John Doe', 25); END TRY BEGIN CATCH IF ERROR_NUMBER() = 2601 BEGIN RAISERROR('Duplicate record found', 16, 1); END END CATCH if the INSERT statement violates the unique index on the StudentID field, the error number 2601 will be raised. The IF condition in the CATCH block checks for this error number and raises a custom error message using the RAISERROR statement.

Tuhin Paul · Answer

You can catch the unique index violation error in your SQL query and replace the standard error message with your own custom error message.

Vishal Yelve · Answer

Hi Ramco, Do refer below link which shows complete implementaion https://www.codeproject.com/Articles/1130113/Best-Ways-of-Implementing-Uniqueness-or-Unique-Key else try { } catch(SqlException ex) { if(ex.Number == 2601 || ex.Number == 2627) { // Violation in one on both... lblErrorMessage.text = "Duplicate record found"; } } OR try { } catct(Exception ex) { if(ex.Message.Contains("UNIQUE KEY constraint")) lblErrorMessage.text="[your unique field] is insert before."; }

Amit Mohanty · Answer

Try this try { // Your code to insert a record into the database } catch (SqlException ex) { if (ex.Number == 2601) // Check if the error is due to a unique index violation { // Display your custom error message Console.WriteLine("Duplicate record found"); } else { // Handle other exceptions as needed Console.WriteLine("An error occurred: " + ex.Message); } }

Ramco Ramco · Answer

Hi AMit It is giving message ex does not contain a definition for number Thanks

Unique Index

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