using indexer as automatic implementing properties

prashant jadhav

dear friends

i was trying to use indexer as auto-implementing properties as i think that indexer is nothing but properties just the difference is its syntax but i got an exception which was something about stack over flow i don't know why it showing so though i have not done any infinite looping or recursion i will try to attach screen print of program which i did please help me what wrong i did.

using System;

namespace IndexerExample

{

class Employee

{

public int this[int index]

{

get {

return this[index];

}

set {

this[index]=value;

}

class Program

{

static void Main(string[] args)

{

Employee e = new Employee();

e[0] = 2;

Console.WriteLine(e[0]);

Console.ReadLine();

}

3 Replies

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Vulpes12y ago
Auto-implemented indexers are not supported because, unlike 'normal' properties, the compiler has no way of deducing what the type of the backing field must be.

So you always have to implement indexers in the traditional way.
prashant jadhav12y ago
thank u very much vulpes now i got it i thought employments[index]=value; will create virtual memory as autonew linkmatically a implemented properties
Vulpes12y ago
The problem is that your indexer has no backing field and is calling itself recursively which eventually overflows the stack.

An Employee class is not an ideal candidate for an indexer which is normally used with some sort of collection.

However, suppose each Employee can have up to 5 employments which are stored in an integer array using a company code (starting from 1) for the employer:

using System;

namespace IndexerExample
{
class Employee
{
private int[] employments = new int[5];

public int this[int index]
{
get {
return employments[index];
}
set {
employments[index]=value;
}
}
}

class Program
{
static void Main(string[] args)
{
Employee e = new Employee();
e[0] = 2; // first employment has a company code of 2
Console.WriteLine(e[0]);
Console.ReadLine();
}
}
}