when i entered house no in first textbox ..display textbox2.

JAYRAM

plz write quarie.......
i have two fields .......

house no & area

1-1-1 to 1-1- EOB = areaname1.

1-2-1 to 1-2-78 = areaname2 .
1-3-50 to 1-3-70 = areaname3.

i wan code like this...

i have two textboxs......
when i entered house no in first text box display area name in second textbox....

ex- when i entered house no: textbox1 1-1-30 textbox2 shows as areaname1
1-2-1 textbox2 shows as areaname2

6 Replies

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Vulpes13y ago
Accepted answer
Try this:

private int EOB = 99; // or whatever

private void textBox1_Leave(object sender, EventArgs e)
{
string[] items = textBox1.Text.Trim().Split('-');

if (items.Length != 3 || items[0] != "1" || (items[1] != "1" && items[1] != "2" && items[1] != "3"))
{
MessageBox.Show("Not a valid house number. Please amend.");
textBox1.Focus();
return;
}

int house;
int.TryParse(items[2], out house);

switch (items[1])
{
case "1":

if (house < 1 || house > EOB)
{
MessageBox.Show(String.Format("Valid house numbers for this area are 1 to {0}. Please amend.", EOB));
textBox1.Focus();
}
else
{
textBox2.Text = "areaname1";
}

return;

case "2":

if (house < 1 || house > 78)
{
MessageBox.Show("Valid house numbers for this area are 1 to 78. Please amend.");
textBox1.Focus();
}
else
{
textBox2.Text = "areaname2";
}

return;

case "3":

if (house < 50 || house > 70)
{
MessageBox.Show("Valid house numbers for this area are 50 to 70. Please amend.");
textBox1.Focus();
}
else
{
textBox2.Text = "areaname3";
}

return;
}
}
Vulpes13y ago
OK, try this revised version:

private int EOB = 99; // or whatever

private void textBox1_Leave(object sender, EventArgs e)
{
string[] items = textBox1.Text.Trim().Split('-');
string area = items[0] + "-" + items[1];

if (items.Length != 3 || !(area == "1-1" || area == "1-2" || area == "1-3" || area == "2-1") )
{
MessageBox.Show("Not a valid house number. Please amend.");
textBox1.Focus();
return;
}

int house;
int.TryParse(items[2], out house);

switch (area)
{
case "1-1":

if (house < 1 || house > EOB)
{
MessageBox.Show(String.Format("Valid house numbers for this area are 1 to {0}. Please amend.", EOB));
textBox1.Focus();
}
else
{
textBox2.Text = "areaname1";
}

return;

case "1-2":

if (house < 1 || house > EOB)
{
MessageBox.Show(String.Format("Valid house numbers for this area are 1 to {0}. Please amend.", EOB));
textBox1.Focus();
}
else
{
textBox2.Text = "areaname2";
}

return;

case "1-3":

if (house < 50 || house > 70)
{
MessageBox.Show("Valid house numbers for this area are 50 to 70. Please amend.");
textBox1.Focus();
}
else
{
textBox2.Text = "areaname3";
}

return;

case "2-1":

if (house < 1 || house > EOB)
{
MessageBox.Show(String.Format("Valid house numbers for this area are 1 to {0}. Please amend.", EOB));
textBox1.Focus();
}
else
{
textBox2.Text = "areaname4";
}

return;
}

}
JAYRAM13y ago
yes...correct
Vulpes13y ago
Well, the code I posted earlier should deal with the three ranges you gave in your original post.

However, it's easy to extend it to deal with different or additional ranges.

Based on what you've said so far, we now have the following 4 ranges:

1-1-1 to 1-1-EOB
1-2-1 to 1-2-EOB (rather than 1-2-1 to 1-2-78)
1-3-50 to 1-3-70
2-1-1 to 2-1-EOB (areaname4)

Can you confirm that this is correct and complete and I'll adjust the code accordingly.
JAYRAM13y ago
v.v. thanx .........

but above code is working only 1-1-1 to 1-1-eob .....

how to write code when house no ex:1 1-2-1 to 1-2-eob
ex:2 2-1-1 to 2-1-eob..

plz help me...
Pankaj Pandey13y ago
fix textbox property postback is true and write your login on text_changed event of textbox