Write a C# class Factors having function static int CountOddFactors(in

Logic:-

1st point:- 1 and the number itself will always be the factor.

2nd point:- The factors will always be within the mid of the number, which means if you have a number 10, then all its factors will be within 5, so there is no point to check the divisibility after the midpoint.

3rd point:- Odd means not divisible by 2.

considering all these points in mind the program will be

class Program
{
static void Main(string[] args)
{
Console.WriteLine(CountOddFactors(110));
Console.ReadLine();
}
public static int CountOddFactors(int number)
{
int count=0;
int mid= number/2;
for (i = 2; x <= mid; i++)
{
if ((num%2==0)&&(num % x == 0))
{
count++;
}
}
int total= count+2; // 2= 1 and number
return total;
}
}

1 Reply

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Sachin Singh5y ago
Logic:-
1st point:- 1 and the number itself will always be the factor.
2nd point:- The factors will always be within the mid of the number, which means if you have a number 10, then all its factors will be within 5, so there is no point to check the divisibility after the midpoint.
3rd point:- Odd means not divisible by 2.

considering all these points in mind the program will be
class Program
    {
        static void Main(string[] args)
        {

         Console.WriteLine(CountOddFactors(110));
Console.ReadLine();
        }

  public static int CountOddFactors(int number)
{

          int count=0;
         int mid= number/2;
            for (i = 2; x <= mid; i++)
            {
                if ((num%2==0)&&(num % x == 0))
                {
                   count++;
                }
            }
       int total= count+2; // 2= 1 and number
            return total;

}
    }