how to create an interface automatically of labes/textboxes

Question

how to create an interface automatically of labes/textboxes, based on the structure of my tables in the database;
I would like know if someone has source code, link or some help code to realize this.
in c#

Pankaj Rawat · Answer

Hi Greg. Suppose your table name is Contact_List First in Design Page. create a Div. In Code Behind. here i create a table at runtime.then add table row in it and then create two table cell . protected void Page_Load(object sender, EventArgs e) { If(!IsPostback) { DataTable dt_tableField=new DataTable(); using(SqlConnection conn=new SqlConnection(ConfigurationManager.ConnectionString["ApplicationServices"].connectionString)) { conn.Open(); sqlCommand cmd=conn.CreateCommand(); cmd.CommandText="Select Column_Name from INFORMATION_SCHEMA.COLUMNS where Table_Name='Contact_List' order By Oridinal Position"; SqlDataReader reader_Object=cmd.ExecuteReader(); dt_tableField.load(reader_Object); conn.close(); } if(dt_tableField.rows.count>0) { Table newtable_Obj=new Table(); TableRow newtablerow_Object; foreach(DataRow dtrow in dt_tableField.rows) { newtablerow_Object=new TableRow(); TableCell newtablecell_Object=new TableCell(); TableCell newtablecell_Object2=new TableCell(); Label labelObject=new Label(); labelObject.ID="lbl"+dtrow[0].tostring(); labelObject.Text=dtrow[o].ToString(); newtablecell_Object.Control.Add(labelObject); Textbox textboxObject=new Textbox(); textbox.ID="txt"+dtrow[0].ToString(); newtablecell_Object2.Controls.Add(textboxObject); newtablerow_Object.Cells.Add(newtablecell_Object); newtablerow_Object.Cells.Add(newtablecell_Object2); newtable_Obj.Controls.ADd(newtablerow_Object); } CreateInterface.Control.Add(newtable_Obj); } } } Similarly you can create a button and add event to it at runtime. i hope this will help you.

greg dorian · Answer

it looks great but i´m using windows form... this code behind, i´ll use in winform thx!!

how to create an interface automatically of labes/textboxes

Answers (2)