number of permutations in c language

#include
 

void swap(int *,int*);
 
void permute(void);
 
int noofpermutations();
 
void display(void);
 

int m,n,noofterms,count=0;
 
int a[100];
 

void swap(int *p1,int *p2)
 
{   int temp;
 
temp = *p1;
 
*p1 = *p2;
 
*p2 = temp;
 
}
 

int noofpermutations()
 
{   int permutations=1,x;
 
for(x=1;x<=noofterms;x++)
 
permutations=permutations*x;
 
return permutations;
 
}
 

void display()
 
{   int x;
 
for(x=0;x 
printf("%d  ",a[x]);
 
printf("\n");
 
count++;
 
}
 

void permute()
 
{   int x,y;

while(count 
{   for(y=0;y 
{  swap(&a[y],&a[y+1]);
 
display();
 
}
 
swap(&a[0],&a[1]);
 
display();
 
for(y=noofterms-1;y>0;y–)
 
{  swap(&a[y],&a[y-1]);
 
display();
 
}
 
swap(&a[noofterms-1],&a[noofterms-2]);
 
display();
 
}
 
}
 

main()
 
{   int x;

printf("Enter no. of terms : ");
 
scanf("%d",&noofterms);
 
printf("Enter the terms : ");
 
for(x=0;x 
scanf("%d",&a[x]);
 
printf("\nPermutations are : \n");
 
permute();
 
printf("\nTotal Permutations : %d",noofpermutations());
 
return 0;
 
}