pass ID in @html.actionlink

Chandrakant Verma

hi,

view:

@using (Html.BeginForm())
{
@Html.ValidationSummary(true, "Login Failed, check details");
<div>
<br />
<fieldset>
<legend>Login Formlegend>
<div class="editor-label">@Html.LabelFor(u => u.UserName)div>
<div class="editor-field">
@Html.TextBoxFor(u => u.UserName)
@Html.ValidationMessageFor(u => u.UserName)
div>
<div class="editor-label">@Html.LabelFor(u => u.Password)div>
<div class="editor-field">
@Html.PasswordFor(u => u.Password)
@Html.ValidationMessageFor(u => u.Password)
div>
<br />
<input type="submit" value="Log In" />
<button class="btn btn-lg btn-success btn-block" type="submit">@Html.ActionLink("Login", "Login", "Home", new { /* ID TO BE PASSED*/ }, null)button>
fieldset>
div>
}

controller:

public ActionResult Index()
{
return View();
}
[ChildActionOnly]
public ActionResult Login()
{
return PartialView("_Login");
}
[HttpPost]
//[ValidateAntiForgeryToken]
public ActionResult Login(Models.Account objUser)
{
if (ModelState.IsValid)
{
using (MyDatabaseEntities db = new MyDatabaseEntities())
{
var obj = db.Accounts.Where(a => a.UserName.Equals(objUser.UserName) && a.Password.Equals(objUser.Password)).FirstOrDefault();
if (obj != null)
{
Session["UserName"] = obj.UserName.ToString();
Session["IsAdmin"] = obj.IsAdmin.ToString();
return RedirectToAction("Index", "Account");
}
}
}
// return View("Dashboard/Index");
return View(objUser);
}

i want login controller to be executed whn login is clicked. please suggest what id is to be passed from the view to execute public ActionResult Login(Models.Account objUser) controller.

6 Replies

Know the answer? Post it — somebody with the same question will find it here.

Ramesh Palanivel9y ago
Hi Chandrakanth,

set the break point for your controller in check whether it comes Login action method or not.. I think while you click the submit the button , it should come your action result.. Kindly set break point and test.
Saineshwar Bageri9y ago
It is your View

@using (Html.BeginForm("Login", "Home" ))
{
@Html.ValidationSummary(true, "Login Failed, check details");

Login Form

@Html.LabelFor(u => u.UserName)

@Html.TextBoxFor(u => u.UserName)
@Html.ValidationMessageFor(u => u.UserName)

@Html.LabelFor(u => u.Password)

@Html.PasswordFor(u => u.Password)
@Html.ValidationMessageFor(u => u.Password)

//this submit button will post your data to controller...

}

You Action method

[HttpGet]
public ActionResult Login()
{
return View();
}

[HttpPost]
public ActionResult Login(Model value)
{

return View();
}
Chandrakant Verma9y ago
@ramesh
tried that . after login click it remains on the same page, it refreshes and comes again the same page.
Chandrakant Verma9y ago
i want my login action (validation controller) to be passed when user clicks this button-
<button class="btn btn-lg btn-success btn-block" type="submit">@Html.ActionLink("Login", "Login", "Home", new { /* ID TO BE PASSED*/ }, null)button>

please tell me if my login controller needs to be modified.
Ramesh Palanivel9y ago
Hi Verma,

you don't need to write the button code in your view,
Change your view like that,
@using (Html.BeginForm("Login", "Home",  new {},
        FormMethod.Post,
        new { enctype = "multipart/form-data" }))
    {
        @Html.ValidationSummary(true, "Login Failed, check details");

        <div>

            <br />

            <fieldset>
                <legend>Login Formlegend>
                <div class="editor-label">@Html.LabelFor(u => u.UserName)div>
                <div class="editor-field">
                    @Html.TextBoxFor(u => u.UserName)
                    @Html.ValidationMessageFor(u => u.UserName)
                div>
                <div class="editor-label">@Html.LabelFor(u => u.Password)div>
                <div class="editor-field">
                    @Html.PasswordFor(u => u.Password)
                    @Html.ValidationMessageFor(u => u.Password)
                div>
                <br />
                <input type="submit" value="Log In" />   //this submit button will post your data to controller...
            fieldset>
        div>
    }
Saineshwar Bageri9y ago
Hi Chandrakant Verma

In this way you can pass Ids in Action Link

@Html.ActionLink("Back to List", "Index", new { id1 = 1, id2 = 3 })

@Html.ActionLink("Back to List", "Index", new { id1 = Model.ID1, id2 = Model.ID2 })