return the sum of the numbers in the parameter list.

Question

Create the method public static int Sum(List numbers) in the exercise template. The method is to return the sum of the numbers in the parameter list. List int > numbers = new List int >(); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); Console.WriteLine(Sum(numbers)); numbers.Add(5); numbers.Add(1); Console.WriteLine(Sum(numbers));

Avnish Kumar · Answer

Try this public static class Program { public static void Main( string [] args) { List numbers = new List(); int result = Sum(numbers); Console.WriteLine( "sum of all numbers {0}" , Convert.ToString(result)); } public static int Sum(List numbers) { numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); } }

kumar kashyap pandey · Answer

using System; using System.Collections.Generic; using System.Linq; namespace ListSum { class Program { static void Main( string [] args) { List int > numbers = new List int >(); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); Console.WriteLine(Sum(numbers)); numbers.Add(5); numbers.Add(1); Console.WriteLine(Sum(numbers)); } private static int Sum(List int > numbers) { return numbers.Sum(); } } }

Bhawna Tuteja · Answer

Use LinQ and then use Sum function to List

Sankar B · Answer

Hi, You can try this. static void Main(string[] args) { List numbers = new List (); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); Console.WriteLine(Sum(numbers)); numbers.Add(5); numbers.Add(1); Console.WriteLine(Sum(numbers)); } public static int Sum(List number) { return number.Sum(); }

Jignesh Kumar · Answer

static void Main( string [] args) { int result = Sum(); Console.WriteLine( "sum of all numbers" , Convert.ToString(result)); }

Nemohoez Dogg · Answer

public static void Main( string [] args) { int result = Sum(); } public static int Sum() { List int > numbers = new List int >(); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); } } } hey this code does not return anything??

Jignesh Kumar · Answer

public static void Main( string [] args) { int result = Sum(); } public static int Sum() { List int > numbers = new List int >(); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); } } }

Ecco Suprastyo · Answer

Hello, you can try this : static void Main( string [] args) { List int > numbers = new List int >(); int result = Sum(numbers); } public static int Sum(List int > numbers) { numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); }

Mngaro Mwazenje · Answer

public static void Main( string [] args) { int result = Sum(); } public static int Sum(List int > numbers) { // List numbers = new List (); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); } } } like this? i get error!! Program.cs(10,20): error CS7036: There is no argument given that corresponds to the required formal parameter 'numbers' of 'Program.Sum(List )' [C:\Users\mngar\Desktop\school\coding-exercises\part3\lists\exercise_76\exercise_76.csproj] Program.cs(23,28): error CS1061: 'List ' does not contain a definition for 'Sum' and no accessible extension method 'Sum' accepting a first argument of type 'List ' could be found (are you missing a using directive or an assembly reference?) [C:\Users\mngar\Desktop\school\coding-exercises\part3\lists\exercise_76\exercise_76.csproj]

Rajanikant Hawaldar · Answer

public static int Sum(List numbers) { return numbers.Sum(); } // or public static int Sum(List numbers) { return numbers.AsQueryable.Sum(); }

Jignesh Kumar · Answer

Hi Mngaro , You no need to pass List in parameter, you can write method like below, And you can call methiod like this, int result = Sum(); public static int Sum() { List int > numbers = new List int >(); numbers.Add(3); numbers.Add(2); numbers.Add(6); numbers.Add(-1); numbers.Add(5); numbers.Add(1); return numbers.Sum(); }

return the sum of the numbers in the parameter list.

Answers (11)