what will be the value of b?? int a = 2; int b = a++ + a++;

int a=3; int b =4; a=a&2;a=a|b

6

Really sorry.... It happened by my poor internet connection....

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

a= 4 and b = 5

value of a= 4 and b = 5

Depending on the compiler you use... This is a bad programming style

5

b=5

int a = 2; int b = a++ + a++; //right to left value of first a++=2 and then a=3 so second a++=3 after that a=4 b=3+2; b=5;

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4

5

5

5

5

5

5

5

5

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5

int a = 2; int b = a++; int c = a++; int d = b + c; Console.WriteLine("b={0}", b); Console.WriteLine("c={0}", c); Console.WriteLine("d={0}", d); Console.ReadLine();

int a = 2; int b = a++; int c = a++; int d = b + c; Console.WriteLine("b={0}", b); Console.WriteLine("c={0}", c); Console.WriteLine("d={0}", d); Console.ReadLine();

a=2; b=a++ + a++; As we know in an assignment expression assocciativity is right--> left. so here right side a value 2 is taken as the operand and after that a's value 2 increments to 3, and then left side a's value becomes 3. so 3 is taken as another operand and after that 3 is increments to 4. but the addition and assignment performs before a's value becomes 4.

a=2; b=a++ + a++; As we know in an assignment expression assocciativity is right--> left. so here right side a value 2 is taken as the operand and after that a's value 2 increments to 3, and then left side a's value becomes 3. so 3 is taken as another operand and after that 3 is increments to 4. but the addition and assignment performs before a's value becomes 4.