Write a Python function that finds the first non-repeating character in a given string. If every character repeats, return None. The function should be case-sensitive, meaning 'A' and 'a' should be considered different characters.

def first_non_repeating_char(string):
    char_count = {}
    # Count the occurrences of each character in the string
    for char in string:
        char_count[char] = char_count.get(char, 0) + 1
    # Find the first character with count 1
    for char in string:
        if char_count[char] == 1:
            return char
    return None
input_string = "aaAbbccddeeffK"
result = first_non_repeating_char(input_string)
print("First non-repeating character:", result)  # Output: A

please find below solution
`string = “hello”
index = -1
fnc = “”

if len(string) == 0 :
print(“EMTPY STRING”);

for i in string:
if string.count(i) == 1:
fnc += i
break
else:
index += 1
if index == len(string)-1 :
print(“All characters are repeating “)
else:
print(“First non-repeating character is”, fnc)`